Information Technology Reference
In-Depth Information
In the steady state of the system, all the differential terms are equal to zero
(see Equation (9)).
⎧
⎨
0=
−
ω
1
×
P
0
+
ω
2
×
P
1
0=
ω
1
×
P
j−
1
−
(
ω
1
+
ω
2
)
×
P
j
+
ω
2
×
P
j
+1
(9)
⎩
0=
ω
1
× P
N−
1
+
ω
2
× P
N
So, by simplifying the system above and considering the normalization
equation:
j
=0
P
j
= 1 we obtain the steady probabilities of each buffer state
(10).
⎧
⎨
α
j
×
(1
−α
)
if
α
=1
1
−
α
N
+1
P
j
=
(10)
⎩
1
N
+1
if
α
=1
We are especially interested in the starvation and blockage probabilities, re-
spectively, represented by empty and full buffer states given by the following
equations:
⎧
⎨
⎩
1
−α
1
−α
N
+1
if
α
=1
P
0
=
(11)
1
N
+1
if
α
=1
⎧
⎨
⎩
α
N
×
(1
−α
)
1
−α
N
+1
if
α
=1
P
N
=
(12)
1
N
+1
if
α
=1
Based on these two probabilities, the effective production rate of each work
station is defined as function of machine processing rate, machine and the buffer
availabilities (13).
ξ
i
μ
i
+
ξ
i
×
μ
i
×
ρ
i
=
ω
i
×
(13)
λ
i
P
0
.
The system throughput
ψ
is defined as the bottleneck between the two effective
production rates
ρ
1
and
ρ
2
.
ψ
=
min
ω
1
×
Such as:
ξ
1
=1
−
P
N
and
ξ
2
=1
−
μ
1
×
−
P
N
)
μ
2
×
−
P
0
)
(1
(1
P
N
)
,ω
2
×
(14)
μ
1
+
λ
1
×
(1
−
μ
2
+
λ
2
×
(1
−
P
0
)
After some transformations, the system throughput can be re-written as follows:
⎧
⎨
μ
1
×
(1
−α
N
)
μ
1
×
(1
−α
N
+1
)+
λ
1
×
(1
−α
N
)
;
μ
2
×
(1
−α
N
)
ω
1
×
{
min
α
N
)
}
μ
2
×
(1
−
α
N
+1
)+
λ
2
×
α
×
(1
−
if
α
=1
ψ
=
(15)
⎩
N×μ
1
N×λ
1
+(
N
+1)
×μ
1
N×μ
2
ω
×
min
{
,
N×λ
2
+(
N
+1)
×μ
2
}
if
α
=1