Cryptography Reference
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(d) Store all quartets ( l C, i u C , v C , j w C ) defined by all pairs ( l C, i u C )
∈H
and ( v C , j w C )
2 15 . 84 and 1
2 40 in a
∈I
, for all 1
i, j
l, u, v, w
.
(e) For all quartets ( l C, i u C , v C , j w C )in
hash table
J
, do filtering by the following
steps. In each steps, discard the quartets which do not satisfy the con-
ditions and if less than 3 quartets are remained, then go to Step 2 with
another key guessing.
i. Check if l C [0 , 1]
J
v C [0 , 1] = 0, i u C [0 , 1]
j w C [0 , 1] = 0, l C [2]
j
u C [2]
,and v C [2]
j
w C [2]
(2 42 filtering).
∈E
∈E
ii. Compute and check if l X 31 [3]
j
u X 31 [3]
,and v X 31 [3]
j
w X 31 [3]
∈F
(2 8 filtering).
iii. Check if Pr[( F 0 ( l C [6]
F
u C [6]) , 0)
l C [7]
u C [7]] > 0andPr[( F 0
j w C [6]) , 0)
( v C [6]
v C [7]
j w C [7]] > 0(2 5 . 65514 filtering).
iv. Compute ΔT = l X 30 [4]
u X 30 [4] and ΔT = v X 30 [4]
j w X 30 [4], and
check if Pr[( F 1 ( ΔT ) , 0)
u C [6]] > 0andPr[( F 1 ( ΔT ) , 0)
l C [6]
j w C [6]] > 0(2 5 . 65514 filtering).
v. Compute and check if Pr[( F 1 ( l X 31 [4]
v C [6]
u X 31 [4]) ,ΔT )
i
l C [5]
j w X 31 [4]) ,ΔT )
u C [5]] > 0andPr[( F 1 ( v X 31 [4]
v C [5]
j w C [5]] >
0(2 4 . 69704 filtering).
vi. If 3 or more quartets ( l C, i u C , v C , j w C ) remained, record them and
go to Step 3; otherwise, go to Step 2 with another guess.
0
0
0
0
0
10
30r
ͷ ͡
ͷ ͢
ͷ ͡
ͷ ͢
2-(e)-v
2-(e)-ii
0
0
0
31r
ͷ ͡
ͷ ͢
ͷ ͡
ͷ ͢
2-(e)-iv
10
2-(e)-iii
0
0
: Guessed key bytes
: Check points
2-(e)-i
Fig. 3. Filtering of wrong quartets. The numbers nearby the check points indicate the
corresponding steps from 2-(e)-i to 2-(e)-v.
Counting and sorting
3. In the following step 4 to step 12, discard the quartets with each key bytes
guessed in each step which do not satisfy conditions. In each steps, if less
than 3 quartets are remained, then go to Step 2 with another key guessing.
4. Guess the LSB 4 ( K 1[15]) to compute LSB 4 ( SK 1[126]) and its related keys.
For each key and remained quartet, check (a) LSB 4 ( l X 29 [3]
u X 29 [3]) = 0
and (b) LSB 4 ( v X 29 [3]
j
w X 29 [3]) = 0.
 
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