Biomedical Engineering Reference
In-Depth Information
Neumann entropy minimized over all ensemble preparations of the state [ 110 ].
Such a measure may be interpreted as the asymptotic number of pure singlets
necessary to prepare the state by local operations and classical communication.
A practical characterization for mixed state entanglement is available for small
systems [ 111 , 112 ], but an explicit formula for calculating the EOF for a given
density matrix is known only for a pair of two-level systems [ 113 , 114 ]. This is
given by
EOF
[ ρ (
t
)] =
x + log 2 x +
x log 2 x ,
1
C 2
where x ± =(
is the concurrence. The concur-
rence is an entanglement measure itself and is equal to
1
±
[ ρ (
t
)]) /
2, and C
[ ρ (
t
)]
C
[ ρ (
t
)] =
max
(
0
, λ 0 λ 1 λ 2 λ 3 ) ,
(9.18)
where
λ i are the square roots of the eigenvalues of the non-Hermitian matrix
)( σ y σ y ) ρ (
ρ (
t
t
)( σ y σ y )
in decreasing order. Here,
ρ (
t
)
is the density matrix
ρ (
of the potentially entangled 2
×
2system,
t
)
is its complex conjugate, and
0
i
σ y =
(9.19)
i
0
is one of the Pauli matrices.
Let us study the decay of entanglement under phonon-induced pure dephasing.
Since local unitary transformations do not change the amount of entanglement
in the system, we can use the density matrix ˜
e iH L t
e iH L t , with H L =
ρ (
t
)=
ρ (
t
)
E 1 ( |
in the formulas for entanglement (in
this section, we use the explicit tensor product notation for the states of the two-
dot system). Using the method introduced in Sect. 9.2.2.2 and assuming a separable
initial system-reservoir state, we find the elements of the density matrix ˜
1
1
|⊗ I)+
E 2 (I ⊗|
1
1
| )
, instead of
ρ (
t
)
ρ (
t
)
.These
are equal to
ρ 0 ] ij e iA ij ( t )+ B ij ( t ) ,
[
ρ (
˜
t
)] ii =[
ρ 0 ] ii ;
˜
[
ρ (
˜
t
)] ij =[
˜
(9.20)
with
A 02 = | g q |
2 sin w q t
A 01 =
,
(9.21)
| g q |
2 cos 2
A 03 =
4
(
q z D
/
2
)
sin w q t
Δ
Et
,
(9.22)
A 12 =
0
,
(9.23)
=
=
,
A 13
A 23
A 03
A 01
(9.24)
= | g q |
2
=
=
=
(
)(
2 n q +
) ,
B 01
B 02
B 13
B 23
cos w q t
1
1
(9.25)
| g q |
2 cos 2
B 03 =
4
(
q z D
/
2
)(
cos w q t
1
)(
2 n q +
1
) ,
(9.26)
B 12 =
4 B 01
B 03 ,
(9.27)
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