Biomedical Engineering Reference
In-Depth Information
(b) If
ℜ
D
>
1
and
ℜ
0
>
1
, then the proportion of infectives persists uniformly.
.
That is, the proportion of infectives in the total population goes to zero while
the total population is decreasing at a geometric rate.
(d) If
(c) If
ℜ
D
<
1
and
ℜ
0
<
1
,then
lim
t
→
∞
(
s
(
t
)
,
i
(
t
)) = (
1
,
0
)
1
, then the proportion of infectives persists uniformly.
That is, the proportion of infectives in the total population persists uniformly
while the total population is decreasing at a geometric rate.
ℜ
D
<
1
and
ℜ
0
>
)=
γ
Proof.
Since
f
(
N
N
,
N
increases geometrically when
ℜ
D
>
1 while it
decreases geometrically when
ℜ
D
<
1. To establish the result, we prove that if in
addition
ℜ
0
<
1, then all solutions
(
s
(
t
)
,
i
(
t
))
of Model (
9
) converge to the disease-
free equilibrium point
1 we proceed exactly as in
the proof of Theorem
4.1
and use Theorem 4.6 in [
18
] to prove that as
t
(
1
,
0
)
as
t
→
∞
.However,if
ℜ
0
>
→
∞
the
proportion of infective population persists uniformly.
5
Ricker Recruitment Function
If new recruits are governed by the Ricker model,
)=
(
1
−
γ
)
γ
N
e
k
−
N
f
(
N
,
2
and 0
<
k
<
,then
N
∞
=
k
for all
N
>
0 and the total population is asymptotically
−
γ
1
constant. If, in addition
ℜ
0
>
1, then by Theorem
4.1
, the infective population
persists uniformly. However, if
ℜ
0
<
1
,
then the infective population goes extinct
(Theorem
4.1
).
As
k
increases past
2
, the demographic dynamics becomes periodic and
Theorem 1 no longer applies. In [
15
], Elaydi and Yakubu proved that non-trivial
periodic orbits are not globally attracting in autonomous models such as Model
(
1
). Next, we use the following example, Example
5.1
, to illustrate that when the
infective population is nonzero and the demographic
N
-dynamics undergoes period-
doubling bifurcations, then the
N
-dynamics can “drive” both the
S
-dynamics and
I
-dynamics in Model (
5
) (see Figs.
2
-
4
).
1
−
γ
Example 5.1.
In Model (
5
), let
β
t
I
N
)=
(
1
−
γ
)
γ
e
−
β
t
N
N
e
k
−
N
f
(
N
and
φ
=
,
where
t
k
∈
[
1
,
6
]
,
β
t
=
a
+
b
×
(
1
+(
−
1
)
)
,
a
=
20
,
b
=
10
,
γ
=
0
.
1and
σ
=
0
.
01.
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