Biomedical Engineering Reference
In-Depth Information
Example4.3
Consider.
L g = ;.based.on.
Definition.4.6,.we.can.obtain.the.following.distribution.matrices:
S
=
{
*00 * **,
* 01* **,
* 10 * **,
* 11* * *
}
.and.
2
ξ
0.78
0.24
0.24
0.1
0.1
0.64
0.04
0.18
0.64
0.14
0.14
0.04
0.16
0.66
0.06
0.16
( )
1
( )
2
A
=
,
A
=
,
0.64
0.14
0.14
0.04
0.16
0.66
0.06
0.16
0.54
0.08
0.08
0.02
0.18
0.64
0.04
0.1
..
0.1
0.04
0.64
0.18
0.02
0.08
0.08
0.54
0.16
0.06
0.66
0.16
0.04
0.14
0.14
0.64
( )
( )
3
4
,
.
A
=
A
=
0.16
0.06
0.66
0.16
0.04
0.14
0.14
0.64
0.18
0.04
0.64
0.1
0.1
0.24
0.24
0.78
..
Let.the.state.at.time. t .be
P
(
, )
t
ξ
ξ
ξ
0.1
0.2
0.3
0.4
1
P
(
, )
t
2
Y t
( )
=
=
,
P
(
, )
t
3
P
(
ξ
, )
t
4
Using . Equation.(4.57) ,.one.can.then.obtain
(
)
( )
1
P
ξ
,
t
+
1
=
Y t A Y t
( )
( ) 0.1396,
=
1
(
)
( )
2
P
ξ
,
t
+
1
=
Y t A Y t
( )
( ) 0.2164,
=
2
( )
3
P
(
ξ
,
t
+
1)
=
Y t A Y t
( )
( ) 0.2764,
=
3
( )
4
P
(
ξ
,
t
+
1)
=
Y t A Y t
( )
( ) 0.3676.
=
4
Therefore,.the.state.at.time. t +.1.is
0.1396
0.2164
0.2764
0.3676
Y t +
(
1)
=
.
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