Biomedical Engineering Reference
In-Depth Information
Since
N
L L
N
L L
all
all
0
≤
<
1
for
L
<
L
,
g
2
(
−
+
1)
−
+
.
g
g
one.has
N
L L
N
L L
0
all
0
≤
+
<
1, that is,
−
1
<
C
+
C
<
1.
row
col
2
−
+
1
(
−
+
1)
.
g
g
ProofofLemma4.7
Based.on.the.row.and.column.properties.given.in.Lemmas.
4.
4.and.
4.
5,.one.has
M
C
row
Q Q
−
=
,
1
3
2
.
.
M
C
col
Q Q
−
=
,
1
4
2
.
.
M
C
col
Q Q
−
=
,
3
2
2
.
.
and.with.Lemma.
4.
2,.we.can.get
4
∑
Q M
i
=
.
.
.
i
=
1
The.proof.can.be.completed.by.solving.the.equations.directly.
For. illustration,. the. elements. of.
Q
,
Q
,
Q
,
Q
. for.
M
=. 2. and.
M
=. 4. are.
1
2
3
4
depicted.in.
Figure.A.6
.
ProofofLemma4.8
The.proof.for.Lemma.4.8.is.derived.in.the.same.way.as.that.of.Lemma.
4.
2.
ProofofLemma4.9
The.proof.of.Lemma.4.9.is.derived.in.the.same.way.as.that.of.Lemma.
4.
3.
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