Biomedical Engineering Reference
In-Depth Information
By. adding. columns. 1. and. 4. and. then. subtracting. columns. 2. and. 3,. we.
can.get
0.78
0.64
0.64
0.54
0.1
0.04
0.04
0.02
0.24
0.14
0.14
0.08
0.24
0.14
0.14
0.08
0.4
0.4
0.4
0.4
+
+
=
.
.
.
as. there. are. two. positions. that. contain. don't-care. bits. only. (i.e.,. *00 ** *. and.
*00* ** )..Thus
N
L L
2
5
0
N
=
2, and
C
=
=
=
0.4.
.(Using.Lemma.4.4)
0
row
+
1
.
g
By.adding.rows.1.and.4.and.then.subtracting.rows.2.and.3,.we.can.get
([0.78
0.24
0.24
0.1]
+
[0.54
0.08
0.08
0.02])
([0.64
0.14
0.14
0.04]
+
[0.64
0.14
0.14
0.04])
=
[0.04
0.04
0.04
0.04]
.
.
as.there.is.only.a.single.position.that.contains.all.the.actual.bits.(i.e.,.* 00 ***)..Thus
N
L L
1
25
all
N
=
1, and
C
=
=
=
0.04.
(Using.Lemma.4.5)
all
col
(
)
2
+
1
g
.
ProofofLemma4.6
If.
ξ ∈ ,. C row . and. C col . are. both. nonnegative.. Otherwise,. they. are. both.
nonpositive.
Apparently,
Z
N N
+
L L
+
0
1
0
all
g
N
L L
N
L L
0
all
g
+
0
1
+
1
+
1
.
g
.
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