Biomedical Engineering Reference
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Z
Z
flip rightmost bit
0 1 ... 1
1 0 1 0 0
1 1
0 1 ... 1
1 0 1 0 1
1 1
(a)
V k
ξ n
(b)
0 1 ... 1
1 0 1 0 0
1 1
V k
ξ n
0 1 ... 1
1 0 1 0 0
1 1
V k
ξ i
0 1 ... 1
1 0 1 0 0
1 1
W c,k = N
Figure a.4
Visualization.of.the.proof.of.Lemma.4.4.
where. N .is.the.size.of. K ′,.specifying.the.number.of.possible.pasting.positions.
in. ξ .that.make.the.pasted.region.contain.don't-care.bits.(*).only..If.
ξ ∈ ,. C row .is.
positive.or.zero;.otherwise,. C row .is.negative.or.zero..Thus,.the.proof.is.completed.
Z
ProofofLemma4.5
Based.on.the.definition.of.
( )
a mn
i
.given.in.Equation.(4.54),.consider
L L
L L
g
g
( )
i
( )
i
a
a
=
K
∆ ξ
(
,
V
′ ξ
;
,
V
)
mn
mn
i
k
n
k
.
(A.17)
ξ
Z
ξ
Z
c
=
0
k
=
0
m
m
(
,
V
;
,
G
)
(
,
V
;
,
G
)
×
∆ ξ
ξ
∆ ξ
ξ
k
m
c k
,
k
m
c k
,
i
i
.
ξ
Z
ξ
Z
m
m
and. for. any. particular.
ξ ∈ . (note:. Z. can. be. Z odd . or. Z even ),. as. shown. in.
Figure A.5 ,. three.cases.can.be.obtained.as.follows:
Z
.
a.. For.any.copying.position. c ,.which.causes.some.actual.bits.of. ξ .to.be.
located.outside.
G c k ,.it.is.possible.to.lip.the.rightmost.of.those.bits.to.
find.a.corresponding.
,
ξ
Z
.such.that
m
∆ ξ
(
,
V
;
ξ
,
G
)
= ∆ ξ
(
,
V
;
ξ
,
G
).
.
i
k
m
c k
,
i
k
m
'
c k
,
.
 
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