Biomedical Engineering Reference
In-Depth Information
Z
Z
flip rightmost bit
0 1 ... 1
1 0 1 0 0
1 1
0 1 ... 1
1 0 1 0
1
1 1
(a)
V
k
ξ
n
(b)
0 1 ... 1
1 0 1 0 0
1 1
V
k
ξ
n
0 1 ... 1
1 0 1 0 0
1 1
V
k
ξ
i
0 1 ... 1
1 0 1 0 0
1 1
W
c,k
=
N
Figure a.4
Visualization.of.the.proof.of.Lemma.4.4.
where.
N
.is.the.size.of.
K
′,.specifying.the.number.of.possible.pasting.positions.
in.
ξ
.that.make.the.pasted.region.contain.don't-care.bits.(*).only..If.
ξ ∈
,.
C
row
.is.
positive.or.zero;.otherwise,.
C
row
.is.negative.or.zero..Thus,.the.proof.is.completed.
Z
ProofofLemma4.5
Based.on.the.definition.of.
( )
a
mn
i
.given.in.Equation.(4.54),.consider
L L
−
L L
−
g
g
∑
∑
∑
∑
( )
i
( )
i
a
−
a
=
K
∆ ξ
(
,
V
′ ξ
;
,
V
′
)
mn
mn
i
k
n
k
.
(A.17)
ξ
∈
Z
ξ
∈
Z
′
c
=
0
k
=
0
m
m
∑
∑
(
,
V
;
,
G
)
(
,
V
;
,
G
)
×
∆ ξ
ξ
−
∆ ξ
ξ
k
m
c k
,
k
m
c k
,
i
i
.
ξ
∈
Z
ξ
∈
Z
′
m
m
and. for. any. particular.
ξ ∈ . (note:. Z. can. be.
Z
odd
. or.
Z
even
),. as. shown. in.
Figure A.5
,.
three.cases.can.be.obtained.as.follows:
Z
.
a.. For.any.copying.position.
c
,.which.causes.some.actual.bits.of. ξ .to.be.
located.outside.
G
c k
,.it.is.possible.to.lip.the.rightmost.of.those.bits.to.
find.a.corresponding.
,
ξ
∈
Z
′
.such.that
m
′
∆ ξ
(
,
V
;
ξ
,
G
)
= ∆ ξ
(
,
V
;
ξ
,
G
).
.
i
k
m
c k
,
i
k
m
'
c k
,
.
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