Cryptography Reference
In-Depth Information
which is easily seen to be a ring. Similarly, when the R j are groups, then this
is a direct sum of groups, which is again a group.
We conclude this section with some more comments on Example A.9, since
we will need these ideas, particularly in Chapter 11 when we discuss error-
correcting codes.
If α isarootof f ( x ) such that
F p [ x ]
( f ( x )) ,
F p ( α ) =
F q =
then f ( x ) is uniquely characterized by the conditions that f ( α ) = 0 and g ( α )=0
for some g ( x )
F p [ x ]if and only if f ( x ) divides g ( x ). In this case, f is called the
minimal polynomial of α over
F p , and is assumed to be monic. In particular,
a polynomial is called primitive of degree n
N
over
F q if it is a minimal
polynomial over
F q of a primitive element of
F q n .
A.5 Vector Spaces
A vector space consists of an additive abelian group V and a field F together
with an operation called scalar multiplication of each element of V by each
element of F on the left, such that for each r, s
F and each α,β
V the
following conditions are satisfied:
1.
V .
2. r ( )=( rs ) α .
3. ( r + s ) α =( )+( ).
4. r ( α + β )=( )+( ).
5. 1 F α = α .
The set of elements of V are called vectors and the elements of F are called
scalars . The generally accepted abuse of language is to say that V is a vector
space over F .If V 1 is a subset of a vector space V that is a vector space in its
own right, then V 1 is called a subspace of V .
Definition A.39 ( Bases, Dependence, and Finite Generation )
If
is a subset of a vector space V , then the intersection of all subspaces of
V containing
S
S
is called the subspace generated by
S
,or spanned by
S
. If there
is a finite set
S
, and
S
generates V , then V is said to be finitely generated .If
S
=
, then
S
generates the zero vector space. If
S
=
{
m
}
, a singleton set, then
the subspace generated by
S
is said to be the cyclic subspace generated by m .
of a vector space V is said to be linearly independent provided
that for distinct s 1 ,s 2 ,...,s n S
A subset
S
, and r j
F for j =1 , 2 ,...,n ,
n
r j s j =0 implies that r j =0 for j =1 , 2 ,...,n.
j =1
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