Biomedical Engineering Reference
In-Depth Information
EXAMPLE PROBLEM 12.3
Consider a membrane in which there is an active
K þ pump, passive channels for
K þ and
Cl ,
and a non-steady-state initial concentration of [
KCl
] on both sides of the membrane. Find an
K þ pump.
expression for the active
Solution
From space charge neutrality,
J Cl ¼ J K ,or
m K Z K K ½ dv
dx KT
m K dK ½
dx
J K ¼ J p
q
m Cl dCl ½
dx
J Cl ¼m Cl Z Cl Cl ½ dv
dx KT
q
K þ pump. Solving for dv
dx
where
J p
is the flow due to the active
using the
J Cl equation with
Z Cl ¼
1gives
d ½ Cl
dx
dv
dx ¼ KT
q ½ Cl
By space charge neutrality,
Cl ½ ¼ K ½
, which allows rewriting the previous equation as
d ½ K þ
dx
dv
dx ¼ KT
q ½ K þ
J K equation with dv
dx
At steady state, both flows are zero, and with
Z K ¼
1, the
substitution is
given as
m K ½ K þ dv
dx KT
m K
q
d ½ K þ
dx
J K ¼
0
¼ J p
d ½ K þ
d ½ K þ
dx
¼ J p m K ½ K þ KT
q ½ K þ
dx KT m K
q
d ½ K þ
dx
2
KT m K
q
¼ J p
Moving
J p
to the left side of the equation, multiplying both sides by
dx
, and then integrat-
ing yields
Z d
Z ½ K þ o
2
KT m K
q
d ½ K þ
J p dx ¼
0
½ K þ i
or
2
KT m K
q d ½ K þ o ½ K þ i
J p ¼
pump was present in this example, then at steady-state, the concentration on both
sides of the membrane would be the same.
Note: If
no
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