Biomedical Engineering Reference
In-Depth Information
EXAMPLE PROBLEM 12.3
Consider a membrane in which there is an active
K
þ
pump, passive channels for
K
þ
and
Cl
,
and a non-steady-state initial concentration of [
KCl
] on both sides of the membrane. Find an
K
þ
pump.
expression for the active
Solution
From space charge neutrality,
J
Cl
¼
J
K
,or
m
K
Z
K
K
½
dv
dx
KT
m
K
dK
½
dx
J
K
¼
J
p
q
m
Cl
dCl
½
dx
J
Cl
¼m
Cl
Z
Cl
Cl
½
dv
dx
KT
q
K
þ
pump. Solving for
dv
dx
where
J
p
is the flow due to the active
using the
J
Cl
equation with
Z
Cl
¼
1gives
d
½
Cl
dx
dv
dx
¼
KT
q
½
Cl
By space charge neutrality,
Cl
½ ¼
K
½
, which allows rewriting the previous equation as
d
½
K
þ
dx
dv
dx
¼
KT
q
½
K
þ
J
K
equation with
dv
dx
At steady state, both flows are zero, and with
Z
K
¼
1, the
substitution is
given as
m
K
½
K
þ
dv
dx
KT
m
K
q
d
½
K
þ
dx
J
K
¼
0
¼
J
p
d
½
K
þ
d
½
K
þ
dx
¼
J
p
m
K
½
K
þ
KT
q
½
K
þ
dx
KT
m
K
q
d
½
K
þ
dx
2
KT
m
K
q
¼
J
p
Moving
J
p
to the left side of the equation, multiplying both sides by
dx
, and then integrat-
ing yields
Z
d
Z
½
K
þ
o
2
KT
m
K
q
d
½
K
þ
J
p
dx
¼
0
½
K
þ
i
or
2
KT
m
K
q
d
½
K
þ
o
½
K
þ
i
J
p
¼
pump was present in this example, then at steady-state, the concentration on both
sides of the membrane would be the same.
Note: If
no