Biomedical Engineering Reference
In-Depth Information
The voltage divider rule easily gives the response,
V
0
10
, due to the 10 V source
¼
8
V
0
10
¼
10
8V
2
þ
8
Next consider the 2 A source active and the other two sources dead, as shown in the following
circuit.
2
Ω
3
Ω
+
2 A
5
Ω
V
0
2
-
2
8
Combining the resistors in an equivalent resistance,
R
EQ
¼
2
kð
3
þ
5
Þ¼
8
¼
1
:
6
O
, and then
2
þ
applying Ohm's law gives
V
0
2
¼
2
1
:
6
¼
3
:
2V.
Finally, consider the response,
V
0
3
, to the 3 A source as shown in the following figure.
2
Ω
3
Ω
+
V
0
3
5
Ω
3 A
-
To find
V
0
3
, note that the 3 A current splits into 1.5 A through each branch (2
þ
3
O
and 5
O
),
and
:
The total response is given by the sum of the individual responses as
V
0
3
¼
1
:
5
2
¼
3V
V
0
¼
V
0
10
þ
V
0
2
þ
V
0
3
¼
8
þ
3
:
2
3
¼
8
:
2V
This is the same result we would have found if we analyzed the original circuit directly using
the node-voltage method.
