Biomedical Engineering Reference
In-Depth Information
EXAMPLE PROBLEM 9.4
For the following circuit, find
I
1
.
1
Ω
I
1
5 A
10/3
Ω
2
Ω
12
Ω
12
Ω
12
Ω
Solution
This circuit problem is solved in two parts, as is evident from the redrawn circuit that follows,
by first finding
I
2
and then
I
1
.
I
2
1
Ω
I
1
5 A
10/3
Ω
2
Ω
12
Ω
12
Ω
12
Ω
R
EQ
To begin, first find
R
EQ
, which, when placed into the circuit, reduces to three parallel resistors
from which
I
2
is calculated. The equivalent resistance is found as
1
R
EQ
¼
1
þ
ð
12
k
12
k
12
Þ ¼
1
þ
12
¼
5
O
1
12
þ
1
12
þ
1
Applying the current divider rule on the three parallel resistors,
10
3
k
2
k
R
EQ
, we have
0
@
1
A
¼
1
5
I
2
¼
5
1A
3
10
þ
1
2
þ
1
5
