Digital Signal Processing Reference
In-Depth Information
Let us now have a closer look at the last term ln fA ( z , n ) g in (7.9)
(
)
N pre
1 a i ( n ) z i
ln{ A ( z , n )} ¼ ln 1 X
(
)
¼ ln X
N pre
a i ( n ) z i
:
(7 : 10)
0
By representing this expression as a product of zeros with modified coefficients b i ( n )
we can write
(
)
(
)
ln X
N pre
¼ ln Y
N pre
a i ( n ) z i
[1 b i ( n ) z 1 ]
0
0
¼ X
N pre
ln{1 b i ( n ) z 1 } :
(7 : 11)
0
By exploiting the following series expansion [3]
ln{1 bz 1 } ¼ 1
1
b k
k z k ,
for jzj . jbj ,
(7 : 12)
that holds for factors that converge within the unit circle, which is the case here since
A ( z , n ) is analytic inside the unit circle [29], we can further rewrite (7.11) [and thus
also (7.10)]
N pre
ln{( A ( z , n )} ¼ X
1
b i ( n )
k
z k
0
1
¼ 1
1
X
N pre
b i ( n )
k
z k
:
(7 : 13)
0
If we now compare (7.9) with (7.13) we observe that the two sums do not have equal
limits. This means that the c i ( n ) are equal to zero for i , 0. For i . 0 we can set the
c i ( n ) equal to the inner sum in (7.13). For i ¼ 0wehave c 0 ( n ) ¼ ln fs ( n ) g from
(7.9). In conclusion, we can state
<
N pre
X
b i m ( n )
i
,
for i . 0,
c i ( n ) ¼
(7 : 14)
0
:
ln{ s ( n )},
for i ¼ 0,
0,
for i < 0 :
 
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