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where u i,j
u ( i,j ) is the approximate solution of (9) at grid point ( i,j ) with
grid size h = 1 as usual. Then applying the Gauss-Seidel iteration to (10) leads
to
2 μ ( C E + C W + C N + C S )+ ʽ u k +1
i,j
=
2 μ C E u i,j +1 + C W u k +1
i− 1 ,j + C S u i +1 ,j + ʾI i,j + ʾg i,j ,
(11)
i,j− 1 + C N u k +1
where
ˈ k ) i,j +1 ,C W =(1
ˈ k ) i,j− 1 ,C N =(1
ˈ k ) i− 1 ,j ,C S =(1
ˈ k ) i +1 ,j .
C E =(1
And we implement the relaxation method to speed up the iteration (11) by
u k +1
i,j = u i,j
ˉ 1 r k +1
i,j ,
(12)
where ˉ 1 > 0 is the relaxation factor. Collecting (12), we have the new concrete
scheme:
= u i,j + ˉ 1 ʾI i,j + ʾg i,j +2 μ [ C E u i,j +1 + C W u k +1
+ C S u i +1 ,j ]
+ C N u k +1
i− 1 ,j
i,j− 1
u k +1
i,j
1+ ˉ 1 2 μ ( C E + C W + C N + C S )+ ʾ
.
(13)
2.2 Split Bregman method for solving ψ
Now, we will apply the split Bregman method [11] to solve (7). First, we define
ˁ ( ˈ ):= μ
ʩ
ˈ ) 2
2 d x ,
(1
|∇
u
|
(14)
and
1 ,
ˈ> 1 ,
Tr ( ˈ ):=
ˈ,
0
ˈ
1 ,
(15)
0 ,
ˈ< 0 .
to make sure that ˈ
[0 , 1] for every iteration [8]. Here, we introduce an auxiliary
variable d and solve the following problem:
d x + ˁ ( ˈ ) subject to d =( d 1 ,d 2 )=
min
ˈ
ʩ | d |
ˈ,
= d 1 + d 2 and ˁ ( ˈ ) is defined in (14). Following the technique in
[11], the split Bregman iteration can be formulated as
where
| d |
b n ) 2 d x , (16)
d x + ˁ ( ˈ )+ ʻ
2
( ˈ n +1 , d n +1 )=argmin
ˈ, d
ʩ | d |
( d −∇
ˈ
ʩ
for given b n ,and
b n +1 = b n +(
ˈ n +1
d n +1 ) .
(17)
 
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