Geoscience Reference
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K y ð x j ;
x i Þ
h i
2 k
2
3 k
l ji ¼ 1 þ
K ð x i ;
x i Þþ
1 þ
h i K ð x i ;
x i Þ
K ð x j ;
x i Þ
K y ð x j ;
x i Þ
1
2 K ð x j ;
2
3 h i
c ji ¼
x i Þ
1 þ
K ð x j ;
x i Þ
X
i 1
h s
2 u
d i ¼ f 0 ð x i Þþk
h s K x ð x i ;
0 ð x s Þ
x s Þ
x s Þþ
s¼0
Thus, starting the calculation by formula ( 2.80 ) from j = 1. We get the values of
solution u 1 ; u 2 ; ...; u m with the error
(x i ). Let us estimate the value of modulus of
the error ʵ (x) from above. Let us introduce the following notation:
ʵ
0 ð x Þ
00 ð x Þ
M ¼ max
½a ; b x Þ
j
j;
N ¼ max
½a ; b u
j
j;
L ¼ max
½a ; b u
j
j;
;
n
o
K y ð x
K x ð x
Q ¼ max
R
;
y Þ
;
y Þ
;
G ¼ max
R
j
K ð x
;
y Þ
j;
n
;
o
K 0 yy ð x
K 0 xy ð x
B ¼ max
R
;
y Þ
;
y Þ
;
h ¼ max
s
h j ;
m
6 BM þ
3h
4 N
3
4 Qh þ
3
10 Bh 2
l ¼
þ LG þ
;
h 2
4 L
n ¼ jj Bm
2
2h
3 N þ
h
6 BL
M þ
þ
Then we have
X
j 1
jj hG þ
2
3 Qh
h
2 e
i
þ jj lh 3
e j
ejjþ
;
i¼0
ejjþ jj Qh X
i 1
jj G
h
2 e
i
s
þ nh 2
e
ejjþ
;
s¼0
e i ¼ u 0 ð x i Þu 0 ð x i Þ . From these formulas we get roughly
where
e j ¼ x j Þuð x j Þ ,
!
ejjþ hQ X
jj G
i 1
s¼0 ejj
i
Þ h 2
e
þ n þ jj QNm
ð
;
"
#
X
X
jj hG þ
j 1
i 1
s¼0 ejj
2
3 Qh
1 þ jj Gh
2
ejjþ jj Gh
2
þ jj th 3
e j
;
i¼0
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