Geoscience Reference
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Neglecting the small quantity R j in this expression, we get a recurrent formula
for determining
, x j 1 .By
differentiating ( 2.75 ) we get a formula to calculate the values of the derivative
ˆ
(x j ) from the values of the function
ˆ
(x)atx = x 0 , x 1 ,
ˆ′
(x):
Z
x
0 ð x Þ ¼f 0 ð x Þþk
K x ð x
u
K ð x
;
x Þuð x Þþk
;
y Þ dy
a
From this equation, we have at x=x i
Z
x s þ 1
X
i 1
0
ð x i Þ ¼f 0 ð x i Þþk
K x ð x i ;
u
K ð x i ;
x i Þuð x i Þþk
y Þuð y Þ dy
ð 2
:
79 Þ
s¼0
x s
where
0 x ðÞ ¼f 0 ðÞþk
u
x ðÞ ¼f ðÞ; u
Ka
ð u
;
ðÞ
Neglecting the quantity
X
i 1
s¼0 f K 0 xy ð x i ; Q s Þ
h s
h s
2
3 u 0 ð x s Þ h s þ
4 u 00 ðn s Þ
r i ¼ k
2 x s Þþ
h s
þ K x ð x i ;
00
x s Þ
6 u
ðn s Þg;
ð x s n s ;
Q s y x s þ 1 Þ
Equation ( 2.79 ) can be written as:
X
i 1
h s
2 u
0
ð x i Þ ¼f 0 ð x i Þþk
h s K x ð x i ;
0
u
K ð x i ;
x i Þuð x i Þþk
x s Þ uð x s Þþ
ð x s Þ
s¼0
We get
finally the equation for determining
x j Þ :
X
j 1
i¼0 x i Þ K ð x j ;
h i ¼ 0
x j Þ f ð x j Þk
x i Þ l ji þ h i c ji d i
;
ð 2
:
80 Þ
where, for sake of brevity, the following notation is introduced:
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