Geoscience Reference
In-Depth Information
Neglecting the small quantity R
j
in this expression, we get a recurrent formula
for determining
, x
j
−
1
.By
differentiating (
2.75
) we get a formula to calculate the values of the derivative
ˆ
(x
j
) from the values of the function
ˆ
(x)atx = x
0
, x
1
,
…
ˆ′
(x):
Z
x
0
ð
x
Þ
¼f
0
ð
x
Þþk
K
x
ð
x
u
K
ð
x
;
x
Þuð
x
Þþk
;
y
Þ
dy
a
From this equation, we have at x=x
i
Z
x
s
þ
1
X
i
1
0
ð
x
i
Þ
¼f
0
ð
x
i
Þþk
K
x
ð
x
i
;
u
K
ð
x
i
;
x
i
Þuð
x
i
Þþk
y
Þuð
y
Þ
dy
ð
2
:
79
Þ
s¼0
x
s
where
0
x
ðÞ
¼f
0
ðÞþk
u
x
ðÞ
¼f
ðÞ; u
Ka
ð u
;
ðÞ
Neglecting the quantity
X
i
1
s¼0
f
K
0
xy
ð
x
i
;
Q
s
Þ
h
s
h
s
2
3
u
0
ð
x
s
Þ
h
s
þ
4
u
00
ðn
s
Þ
r
i
¼
k
2
uð
x
s
Þþ
h
s
þ
K
x
ð
x
i
;
00
x
s
Þ
6
u
ðn
s
Þg;
ð
x
s
n
s
;
Q
s
y
x
s
þ
1
Þ
Equation (
2.79
) can be written as:
X
i
1
h
s
2
u
0
ð
x
i
Þ
¼f
0
ð
x
i
Þþk
h
s
K
x
ð
x
i
;
0
u
K
ð
x
i
;
x
i
Þuð
x
i
Þþk
x
s
Þ uð
x
s
Þþ
ð
x
s
Þ
s¼0
We get
finally the equation for determining
uð
x
j
Þ
:
X
j
1
i¼0
uð
x
i
Þ
K
ð
x
j
;
h
i
¼ 0
uð
x
j
Þ
f
ð
x
j
Þk
x
i
Þ
l
ji
þ
h
i
c
ji
d
i
;
ð
2
:
80
Þ
where, for sake of brevity, the following notation is introduced:
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