Geoscience Reference
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Equate the integral in ( 2.18 ) to zero. It gives
T ð h Þ ¼c Z
c k ð h Þ dh
;
where c is an arbitrary constant. The integral in ( 2.18 ) will be equal to zero if
X
n
c 1 k
B k k ð k 1 Þ k
!
k ¼ 0
ð 2
:
19 Þ
k ¼ 2
Further integrating of ( 2.18 ) by parts gives
where
T 000 ð h Þc k ð h Þ 3T 00 ð h Þc k ð h Þ T 0 ð h Þc 0 k ð h Þþ 3T 0 ð h Þ c 0 k 2
c
Z 1
J 3 ¼
F k ð h Þ dh
4
k
0
This integral will be equal to zero at
T ð h Þ ¼c Z
Z
c k ð h Þ
c k ð u Þ dudh
If the condition ( 2.16 ) is not met then J 3 =0at
X
n
c 2 k
k
B k k ð k 1 Þð k 2 Þ k
!
¼ 0
k¼3
With the process of integration of ( 2.18 ) continued N times, we obtain
ð 2
:
20 Þ
where
P 2 ð h Þ ¼T 0 ð h Þ=c k ð h Þ...;
P k ð h Þ ¼P 0 k 1 ð h Þ=c k ð h Þ
P 1 ð h Þ ¼T ð h Þ;
but
Z 1
P 0 N ð h Þ F k ð h Þ dh ¼ 0
J N ¼
0
 
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