Geoscience Reference
In-Depth Information
Equate the integral in (
2.18
) to zero. It gives
T
ð
h
Þ
¼c
Z
c
k
ð
h
Þ
dh
;
where c is an arbitrary constant. The integral in (
2.18
) will be equal to zero if
X
n
c
1
k
B
k
k
ð
k
1
Þ
k
!
k
¼ 0
ð
2
:
19
Þ
k
¼
2
Further integrating of (
2.18
) by parts gives
where
T
000
ð
h
Þc
k
ð
h
Þ
3T
00
ð
h
Þc
k
ð
h
Þ
T
0
ð
h
Þc
0
k
ð
h
Þþ
3T
0
ð
h
Þ c
0
k
2
c
Z
1
J
3
¼
F
k
ð
h
Þ
dh
4
k
0
This integral will be equal to zero at
T
ð
h
Þ
¼c
Z
Z
c
k
ð
h
Þ
c
k
ð
u
Þ
dudh
If the condition (
2.16
) is not met then J
3
=0at
X
n
c
2
k
k
B
k
k
ð
k
1
Þð
k
2
Þ
k
!
¼ 0
k¼3
With the process of integration of (
2.18
) continued N times, we obtain
ð
2
:
20
Þ
where
P
2
ð
h
Þ
¼T
0
ð
h
Þ=c
k
ð
h
Þ...;
P
k
ð
h
Þ
¼P
0
k
1
ð
h
Þ=c
k
ð
h
Þ
P
1
ð
h
Þ
¼T
ð
h
Þ;
but
Z
1
P
0
N
ð
h
Þ
F
k
ð
h
Þ
dh ¼ 0
J
N
¼
0
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