Civil Engineering Reference
In-Depth Information
2
()
x
φ
2
ˆ
2
()
i
r
()
()
x
H
S
d
σ
=
ω
ω
ω
r i
r
i
2
Q i
K
i
0
(4.31)
2
()
φ
x
2
2
ˆ
ˆ
i
r
()
()
( )
()
H
0
S
d
S
H
d
ωω
+
ω
ω
ω
i
i
i
2
Q
Q
K
i
i
⎦ ⎭
i
0
0
It is in the following taken for granted that
1
ˆ
()
H
01
=−
κ
=
1
(4.32)
i
ae i
i.e. that
K
=
0
at
ω =
0
. (This is an obvious assumption as the structure is not in
ae i
0
motion at
ω =
.) Introducing
()
2
Sd
ωωσ
=
Q
Q
i
i
0
(4.33)
2
πω
ˆ
()
i
Hd
ωω
=
i
(
)
41
κζ
0
ae
tot
i
i
where
ζ
=−
ζ
ζ
, the following is obtained
tot
i
ae
i
i
2
()
S
()
πω
ω
x
K
φ
i
i
Q
2
2
2
i
r
2
i
σσ σ
≈+=
σ
+
(4.34)
(
)
r
B
R
Q
i
i
i
i
41
κζ
i
ae
tot
i
i
4.3 Single mode three component response calculations
In this second approach it is assumed that the eigen-frequencies are still well spaced out
on the frequency axis, but that each mode shape contain three components, i.e. the dis-
placements
φ , and the rotation φ , as illustrated in Fig. 4.5. Adopting the same
assumptions regarding motion induced load effects as presented in chapter 4.2 above, the
total cross sectional load is given by
φ
and
y
z
(
)
(
)
xt
,
xt
, , , ,
(4.36)
q q
=
+
q
rrr
tot
ae
T
(
)
(4.37)
where:
q
xt
,
=
q
q
q θ
y
z
is the flow induced part of the load, and
T
(
)
xt
,,,,
q
q
q θ
q
rrr
=
(4.38)
ae
y
z
ae
is the motion induced part.
 
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