Civil Engineering Reference
In-Depth Information
(see Fig. 2.14 and Eq. 2.99, and assuming for simplicity that x
Δ
is a constant), each
rendering a base moment contribution
()
( )
()
M
t
GxQt
=
(2.113)
k
M
k
k
such that the total bending moment at the base is
N
()
(2.114)
()
M t
Mt
=
k
k
1
=
Its variance is then given by (see Eq. 2.100)
2
T
T
N
1
1
2
2
()
()
lim
M t
dt
lim
M
t
dt
σ
=
=
M
k
T
T
T
T
→∞
→∞
k
=
1
0
0
T
1
[
] [
]
=
lim
M
++ ++
.....
M
.....
M
M
++ ++
.....
M
.....
M
dt
1
k
N
1
k
N
T
T
→∞
0
T
NN
1
2
∑∑
()
()
lim
M
tM tdt
σ
=
(2.115)
M
n
m
T
T
nm
→∞
==
11
0
As can be seen, the transition from a single summation to a double summation is
necessary to capture all the cross products. Introducing Eqs. 2.112 and 2.113, the
following is obtained:
T
NN
1
L
L
2
∑∑
()( )
(
)
(
)
lim
Gxqxt
,
Gxqxt
,
t
σ
=
M
M
n
y
n
M
m
y
m
T
N
N
T
nm
→∞
==
11
0
2
T
NN
1
L
∑∑
()
( )
(
)
(
)
GxGx
lim
qxt
,
qxt
,
t
=
⎜⎟
Mn
Mm
yn
ym
T
N
T
⎝⎠
→∞
nm
11
==
0
2
σ
L
NN
q y
2
∑∑
()
( )
()
GxGx
x
σ
=
ρ
Δ
(2.116)
M
M
n
M
m
q y
N
nm
11
==
(
)
x
where
ρ
Δ
is the covariance coefficient to the distributed load, and where
q y
x
xx
Δ=
. The expression in Eq. 2.116 is equivalent to that which was obtained in
mn
Eq. 2.103.
 
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