Graphics Programs Reference
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U2 =
0.8165
-0.5774
0.7071
0.4082
-0.5774
-0.7071
0.4082
-0.5774
-0.0000
R2 =
2.0000
0
0
0
-1.0000
0
0
0
3.0000
We observe that the columns of U1 are negatives of the corresponding
columns of U2 . Finally,
A*B - B*A
ans =
0
0
0
0
0
0
0
0
0
Problem 13
(a)
If we set X n to be the column matrix with entries x n , y n , z n , and M the
square matrix withentries 1, 1/4, 0; 0, 1/2, 0; 0, 1/4, 1 then X n + 1 = MX n .
(b)
We have X n = MX n 1 = M 2 X n 2 = ... = M n X 0 .
(c)
M = [1, 1/4, 0; 0, 1/2, 0; 0, 1/4, 1];
[U,R] = eig(M)
U=
1.0000
0
-0.4082
0
0
0.8165
0
1.0000
-0.4082
R=
1.0000
0
0
0
1.0000
0
0
0
0.5000
 
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