Graphics Programs Reference
In-Depth Information
(d)
limit(1/(x - 1), x, 1, 'left')
ans =
-inf
(e)
limit(sin(1/x), x, 0, 'right')
ans =
-1 .. 1
This means that every real number in the interval between
−
1 and
+
1is
a “limit point” of sin(1
/
x
)as
x
tends to zero. You can see why if you plot
sin(1
/
x
) on the interval (0, 1].
ezplot(sin(1/x), [0 1])
sin(1/x)
1
0.5
0
−
0.5
−
1
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
x
Problem 6
(a)
symsknrxz
symsum(kˆ2, k, 0, n)
ans =
1/3*(n+1)^3-1/2*(n+1)^2+1/6*n+1/6
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