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ans =
0000000000
ans =
0000000000
ans =
0000000000
So the 4th column, representing total inter-industry output, is the sum of
columns 1 through 3; the 8th column, representing total “final demand,” is
the sum of columns 5 through 7; and the 9th column, representing total
output, is the sum of columns 4 and 8. The matrix
A
of
inter-industry
technical coefficients
is obtained by dividing the columns of
T
corresponding
to industrial sectors (in our case there are three of these) by the
corresponding total inputs. Thus we have
A = [T(:, 1)/T(10, 1), T(:, 2)/T(10, 2), T(:, 3)/T(10, 3)]
A=
0.1425
0.0147
0.0008
0.3020
0.3688
0.1032
0.1214
0.0964
0.0861
0.5658
0.4800
0.1900
0.0684
0.0941
0.0370
0.0015
0.0044
0.0023
-0.1265
0.0165
0.0242
0.4907
0.4050
0.7465
0.4342
0.5200
0.8100
1.0000
1.0000
1.0000
Here the square upper block (the first three rows) is most important, so we
make the replacement
A = A(1:3, :)
A=
0.1425 0.0147
0.0008
0.3020 0.3688
0.1032
0.1214 0.0964
0.0861
If the vector
Y
represents total final demand for the various industrial
sectors, and the vector
X
represents total outputs for these sectors, then the
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