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This gives ( B.62b ), if we take the infimum over all decompositions of f
S( 0 ,T)
of the form f
h as in ( B.15a ), provided u 0 satisfies also ( B.15b ).
To show ( B.62a ) for general f
=
g
+
,weuse( B.21 ), ( B.25 ) to bound
the second row of ( B.60 ), and approximate a general f
S(a,b),u 0 H
; H
+
S( 0 ,T) from BV (J
)
H 1 (J
; V ) to bound the first row of ( B.60 )by o( 1 ) as k
0.
We are now ready to prove the existence Theorem B.2.2 . To this end, we show
that the family
{
} k> 0 is Cauchy in I( 0 ,T) . More precisely, there is C> 0 such
U k (t)
that
C E(k,T )
E(h,T ) .
U k (t)
U h (t)
I( 0 ,T )
+
(B.63)
{
This and ( B.62a ), ( B.62b ) imply that
U k } k> 0 is Cauchy in I( 0 ,T) and that there is
U =
lim k 0 U k (t) I( 0 ,T) with
CE(k,T ). (B.64)
We note that ( B.64 ) with ( B.62a ), ( B.62b ) gives an err or estimate for ( B.12a ),
( B.12b ). To prove ( B.63 ), we recall the definition ( B.55 )of u k (t) and we also define
U(t)
U k (t)
I( 0 ,T )
u k (t)
=
k (t) u k (t)
+
( 1
k (t)) u(t
+
k),
(B.65)
where
k (t)
:=
m
+
1
t/k
∈[
0 , 1
]
,t
J k,m =[
mk, (m
+
1 )k
]
.
(B.66)
Then it follows from ( B.12a ), ( B.12b )thatforall t
J holds
v
u k +
. (B.67)
To prove ( B.63 ), we proceed as follows: we rewrite ( B.67 ) in terms of U k (t) in
( B.13a ), ( B.13b ) with small right hand side. Then ( B.63 ) will be obtained by appli-
cation of Lemma B.3.6 to U k (t)
Au k (t
+
k)
f k (t), u k (t
+
k)
V , V
0
v
K
U h (t) .
H
u k (t) u k (t + k) H u k (t) u k (t + k) H = ku k (t) H ,
k
We have from 0
1 that in
(B.68)
and also in
V
, and for every (a, b)
J , that
u k (t)
I(a,b)
u k (t)
I(a,b) +
u k (t
+
k)
I(a,b)
2
u k (t)
I(a,b + k) .
(B.69)
Lemma B.3.15 Fo r a n y v K
, the following holds :
U k (t) + AU k (t) f k (t + k), U k (t) v V , V
β kU k (t) V U k (t) v V
k (t) U k (t)
k),kU k (t)
+ A
u k (t
+
k)
f k (t
+
.
(B.70)
V , V
Proof We have by ( B.4a )
A
V , V A
+
V , V
U k (t), U k (t)
v
u k (t
k),U k (t)
v
+ A
u k (t
+
k)
A
u k (t
+
k),U k (t)
v
V , V
A
V , V
+ β u k (t + k) u k (t + k) V U k (t) v V
u k (t
+
k),U k (t)
v
=:
I
+
II .
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