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d
=
∈ R
distribution μ of X at t
1is Q -stable, i.e. for any r> 0 there exists a c
such that
1
α 1 z 1 ,...,r
1
α d z d )e i c,z .
μ(z) r
= μ(r
(14.8)
μ(z) = e ψ(z) , it follows from
( 14.8 ) that the characteristic exponent of an α -stable process satisfies for any r> 0
Since we have for the characteristic function
1
α 1 ξ 1 ,...,r
1
α d ξ d )
d .
ψ(r
=
r
ψ(ξ),
ξ
∈ R
(14.9)
We assume that the Lévy measure ν has a Lévy density k ,i.e. ν( d z)
=
k(z) d z and
obtain for
Q =
0 that
1
α 1 ξ 1 ,...,r
1
α d ξ d )
ψ(r
1
cos d
k sym (z) d z
1
α i ξ i z i
=
r
d
R
i
=
1
1
α 1 z 1 ,...,r
1
α d z d )r
1
α 1 −···−
1
α d d z.
) k sym (r
=
( 1
cos
ξ,z
d
R
Now using ( 14.9 ), the Lévy density has to satisfy
1
α 1 z 1 ,...,r
1
α d z d )
1
α 1 +···+
1
α d k sym (z 1 ,...,z d ).
k sym (r
r 1 +
=
(14.10)
d
A simple example of an α -stable Lévy process on
R
is given by the Lévy measure
d
α i 1
1
α 1 −···−
1
α d
2 d
=
1 |
z i |
ν( d z)
c j
1 Q j d z,
(14.11)
j
=
1
i
=
0, 2 d
j
1 c j > 0. The corresponding marginal processes X i , i
where c j
=
1 ,...,d
=
| 1 α i d z
of X are again α -stable processes in
R
with Lévy measure ν i ( d z)
=
c i |
z
1 ,..., 2 d . We plot the density ( 14.11 )for
where
c i depend on d , α and c j , j
=
d =
2, α
= ( 0 . 5 , 1 . 2 ) and c j =
1, j =
1 ,..., 4inFig. 14.2 .
14.3.1 Subordinated Brownian Motion
As in the one-dimensional case, we can obtain Lévy processes by subordination .
For d> 1 there are two possibilities. Using a one-dimensional increasing process or
subordinator G
={
G t :
t
0
}
, the resulting process is given by
X t =
W i G t +
θ i G t , i ∈ R
,t
∈[
0 ,T
]
,
(W 1 ,...,W d ) is a vector of d Brownian motions with
for i
=
1 ,...,d where W
=
i σ j ρ ij ) 1 i,j d . Here, σ i
covariance matrix
Q =
, i
=
1 ,...,d , is the variance of
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