Geoscience Reference
In-Depth Information
Tensile load by impact on bottom (
J
= 1000 kN/m)
250
225
200
v
= 4 m/s
v
= 6 m/s
v
= 8 m/s
v
= 10 m/s
v
= 12 m/s
v
= 6,7 m/s
175
150
125
100
75
50
25
0
0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0
cr oss- section /cir cu m fer en ce geotextile con tain er (
A/S
) [m
2
/m]
Figure G.5
Design chart for required tensile strength in geotextile.
was determined using formulae (G.1) to (G.4). A comparison between the measured
and the calculated fall velocities showed that formulae (G.1) to (G.4) (with
C
d
1.0)
are sufficiently accurate to be used in designing structures with geotextile containers.
=
CALCULATION EXAMPLE
For illustration, the calculation example from Chapter 6 is expanded here. First, the fall
velocity and the corresponding tensile load generated in the geotextile are determined
using the formulae. Then the same exercise is repeated using the design graphs.
2
V
320
100 10
2
1990 1000
1000
⋅
ρρ
−
⋅
−
9817
=
817m/s
9
V
AC
w
w
v
∞
=
⋅
g
g
=
⋅
⋅
.
ρ
⋅
s
C
d
w
2
⋅
2
(
1
1
)
2
V
2
320
(
1990
0
.
5 1000
)
+
+⋅
2
+
⋅
⋅
⋅
′ =
202
V
AC
⋅
w
t
′
ρρ
2
w
2
=
=
02
s
⋅
100
(
)
1 1000
(
1990
1000
)
981
ρ
w
(
g
−
⋅
⋅
⋅
−
⋅
d
w
w
w
10
79 202
h
′
⋅ =
h
′ =
063
=
vt
⋅
⋅
.
9 2
∞
2
h
h
h
h
h
h
′
′
2
h
′
126
0
63
1
26
1
h
h
h
1
79
1
1
−
e
h
e
e
e
e
−
e
e
+
+
e
e
0
.
e
.
−
−
e
e
e
vv
=⋅
∞
h
h
⋅ ′
h
2
h
h
h
h
h
2
1. 6
0 63
1. 6
1
.
e
e
e
e
e
e
.
1.
e
e
.
e
e
−
−
−
79
1
−
3 525
.
+
1 878
.
⋅
3 525
.
−
1
=⋅
.
=
67
.m s
3 525
.
−
1 878
.
⋅
3 525
.
−
1
10 1990 10
18
6
Tv
AJ
S
′
⋅
⋅
⋅
kN
/
m
N
67
233 000
Nm
223
v
=⋅
=
=
7
233
.
The red lines on the graphs (Figures G.1 to G.5) are shown above demonstrating
the same results.
