Civil Engineering Reference
In-Depth Information
Solving:
cos
P
cos
P
cos
P
P
CA
CA
CB
CB
CD
CD
CX
P
=
(5.5.1A-2)
sin
P
sin
P
sin
P
P
CA
CA
CB
CB
CD
CD
CY
0
8944
(
10
.
8944
(
10
.
1
10
.
0
=
0
4472
(
10
.
0
4472
(
10
.
0
10
.
2
7
889
=
2
000
A
E
A
E
A
E
K
11
=
cos
2
CA
CA
L
CA
+
cos
2
CB
CB
L
CB
+
2
CD
CD
L
CD
(5.5.1A-
cos
CA
CB
CD
3)
2
2
2
(
.
8944
)
(
40
)(
200
)
(
.
8944
)
(
40
)(
200
)
(
.
0
)
(
40
)(
200
)
=
+
+
2236
2236
2000
= 9.724 kN/mm
A
E
A
E
K
12
=
K
21
=
sin
CA
cos
CA
L
CA
+
sin
CB
cos
CB
L
CB
+
CA
CB
CA
CB
A
E
sin
CD
cos
CD
L
CD
(5.5.1A-4)
CD
CD
(.
4472
)(
.
8944
)(
40
)(
200
)
(
.
4472
)(
.
8944
)(
40
)(
200
)
(
0
)(
1
.
0
)(
40
)(
200
)
=
+
+
2236
2236
2000
= 0.0 kN/mm
A
E
A
E
A
E
2
CA
CA
L
CA
2
CB
CB
L
CB
2
CD
CD
L
CD
K
22
=
sin
+
sin
+
sin
(5.5.1A-
CA
CB
CD
5)
2
2
2
(
.
4472
)
(
40
)(
200
)
(
.
4472
)
(
40
)(
200
)
(
0
)
(
40
)(
200
)
=
+
+
2236
2236
2000
= 1.431 kN/mm
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