Digital Signal Processing Reference
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where H
1
ðzÞ and H
2
ðzÞ are chosen to be
H
1
ðzÞ¼
0:5 0:5
z
1
1 þ 0:4z
1
H
2
ðzÞ¼
1 þ
z
1
1 þ 0:9z
1
Notice that the obtained H
1
ðzÞ and H
2
ðzÞ are not the unique selections for realization. For example, there is another
way of choosing H
1
ðzÞ¼
0:5 0:5
z
1
1 þ 0:9z
1
and H
2
ðzÞ¼
1 þ z
1
1 þ 0:4z
1
to yield the same HðzÞ. Using the H
1
ðzÞ and
H
2
ðzÞ we have obtained, and with the direct-form II realization, we achieve the cascade formdepicted in
Figure 6.28
.
FIGURE 6.28
Cascade realization for Example 6.13.
The difference equations for the direct-form II realization have two cascaded sections, expressed as
Section 1:
w
1
ðnÞ¼xðnÞ0:4wðn 1Þ
y
1
ðnÞ¼0:5w
1
ðnÞ0:5w
1
ðn 1Þ
Section 2:
w
2
ðnÞ¼y
1
ðnÞ0:9w
2
ðn 1Þ
yðnÞ¼w
2
ðnÞþw
2
ðn 1Þ
c. In order to yield the parallel form of realization, we need to make use of the partial fraction expansion, and we
first let
0:5ðz
2
1Þ
zðz þ 0:4Þðz þ 0:9Þ
¼
H
ð
z
z
¼
A
z
þ
B
z þ 0:4
þ
C
z þ 0:9
where
z¼0
¼
z¼0
¼1:39
A ¼ z
0:5ðz
2
1Þ
zðz þ 0:4Þðz þ 0:9Þ
0:5ðz
2
1Þ
ðz þ 0:4Þðz þ 0:9Þ
z¼0:4
¼
0:5ð
z
2
1Þ
z¼0:4
¼ 2:1
0:5ðz
2
1Þ
zðz þ 0:4Þðz þ 0:9Þ
B ¼ðz þ 0:4Þ
zðz þ 0:9Þ
0:5
z
2
1
zðz þ 0:4Þðz þ 0:9Þ
z¼0:9
¼
0:5
z
2
1
z þ 0:9
z¼0:9
¼0:21
C ¼
zðz þ 0:4Þ
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