Digital Signal Processing Reference
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where H 1 ðzÞ and H 2 ðzÞ are chosen to be
H 1 ðzÞ¼ 0:5 0:5 z 1
1 þ 0:4z 1
H 2 ðzÞ¼ 1 þ z 1
1 þ 0:9z 1
Notice that the obtained H 1 ðzÞ and H 2 ðzÞ are not the unique selections for realization. For example, there is another
way of choosing H 1 ðzÞ¼ 0:5 0:5 z 1
1 þ 0:9z 1 and H 2 ðzÞ¼ 1 þ z 1
1 þ 0:4z 1 to yield the same HðzÞ. Using the H 1 ðzÞ and
H 2 ðzÞ we have obtained, and with the direct-form II realization, we achieve the cascade formdepicted in Figure 6.28 .
FIGURE 6.28
Cascade realization for Example 6.13.
The difference equations for the direct-form II realization have two cascaded sections, expressed as
Section 1:
w 1 ðnÞ¼xðnÞ0:4wðn 1Þ
y 1 ðnÞ¼0:5w 1 ðnÞ0:5w 1 ðn 1Þ
Section 2:
w 2 ðnÞ¼y 1 ðnÞ0:9w 2 ðn 1Þ
yðnÞ¼w 2 ðnÞþw 2 ðn 1Þ
c. In order to yield the parallel form of realization, we need to make use of the partial fraction expansion, and we
first let
0:5ðz 2
zðz þ 0:4Þðz þ 0:9Þ ¼
H ð z z ¼
A
z þ
B
z þ 0:4 þ
C
z þ 0:9
where
z¼0 ¼
z¼0 ¼1:39
A ¼ z
0:5ðz 2
zðz þ 0:4Þðz þ 0:9Þ
0:5ðz 2
ðz þ 0:4Þðz þ 0:9Þ
z¼0:4 ¼ 0:5ð z 2
z¼0:4 ¼ 2:1
0:5ðz 2
zðz þ 0:4Þðz þ 0:9Þ
B ¼ðz þ 0:4Þ
zðz þ 0:9Þ
0:5 z 2 1
zðz þ 0:4Þðz þ 0:9Þ
z¼0:9 ¼ 0:5 z 2 1
z þ 0:9
z¼0:9 ¼0:21
C ¼
zðz þ 0:4Þ
 
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