Digital Signal Processing Reference
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Find the transfer function HðzÞ, the denominator polynomial AðzÞ, and the numerator polynomial BðzÞ.
Solution:
Taking the z-transform on both sides of the previous difference equation, we obtain
Y ðzÞ¼X ðzÞX ðzÞz
2
1:3Y ðzÞz
1
0:36Y ðzÞz
2
Moving the last two terms to the left side of the difference equation and factoring Y ðzÞ on the left side and X ðzÞ on
the right side, we obtain
Y ðzÞð1 þ 1:3z
1
þ 0:36z
2
Þ¼ð1 z
2
ÞX ðzÞ
Therefore, the transfer function, which is the ratio of Y ðzÞ over X ðzÞ, can be found to be
1 z
2
1 þ 1:3z
1
þ 0:36z
2
Y
ð
z
Þ
X ðzÞ
¼
HðzÞ¼
From the derived transfer function HðzÞ, we can obtain the denominator polynomial and numerator polynomial as
AðzÞ¼1 þ 1:3z
1
þ 0:36z
2
and
BðzÞ¼1 z
2
The difference equation and its transfer function, as well as the stability issue of the linear time-invariant system,
will be discussed in the following sections
EXAMPLE 6.4
A digital system is described by the following difference equation:
yðnÞ¼xðnÞ0:5xðn 1Þþ0:36xðn 2Þ
Find the transfer function HðzÞ, the denominator polynomial AðzÞ, and the numerator polynomial BðzÞ.
Solution:
Taking the z-transform on both sides of the previous difference equation, we obtain
Y ðzÞ¼X ðzÞ0:5X ðzÞz
2
þ 0:36X ðzÞz
2
Therefore, the transfer function, that is the ratio of Y ðzÞ to X ðzÞ, can be found as
Y
ð
z
Þ
X ðzÞ
¼ 1 0:5z
1
þ 0:36z
2
HðzÞ¼
From the derived transfer function HðzÞ, it follows that
AðzÞ¼1
BðzÞ¼1 0:5z
1
þ 0:36z
2
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