Digital Signal Processing Reference
In-Depth Information
Choosing the duration of one period, N ¼ 4, we have the following sample values:
xð0Þ¼0; xð1Þ¼1; xð2Þ¼0; and xð3Þ¼1
Using Equation (4.5) ,
xð0Þþxð1Þþxð2Þþxð3Þ
X 3
c 0 ¼ 1
4
xðnÞ¼ 1
4
¼ 1
4 ð0 þ 1 þ 0 1Þ¼0
n ¼0
xð0Þþxð1Þe jp=2 þ xð2Þe jp þ xð3Þe j3p=2
X 3
c 1 ¼ 1
4
xðnÞe j2p1n=4 ¼ 1
4
n ¼0
xð0Þjxð1Þxð2Þþjxð3Þ¼0 jð1Þ0 þ jð1Þ
¼ 1
4
¼j0:5
Similarly, we get
X 3
X 3
c 2 ¼ 1
4
xðnÞe j2p2n=4 ¼ 0; and c 3 ¼ 1
4
xðkÞe j2p3n=4 ¼ j0:5
k ¼0
n ¼0
Using periodicity, it follows that
c 1 ¼ c 3 ¼ j0:5; and c 2 ¼ c 2 ¼ 0
b. The amplitude spectrum for the digital signal is sketched in Figure 4.5 .
c
0.
0.
0.
0 .
0 .
0.
2
4
f
Hz
0
5
1
5
4
3
2
1
3
f
/2
2
s
f
4
s
FIGURE 4.5
Two-sided spectrum for the periodic digital signal in Example 4.1.
As we know, the spectrum in the range of 2 to 2 Hz presents the information of the sinusoid with a frequency
of 1 Hz and a peak value of 2j:c 1 j: ¼ 1, which is obtained from converting two sides to one side by doubling the
two-sided spectral value. Note that we do not double the direct-current (DC) component, that is, c 0 .
4.1.2 Discrete Fourier Transform Formulas
Now let us concentrate on development of the DFT. Figure 4.6 shows one way to obtain the DFT
formula.
 
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