Biomedical Engineering Reference
In-Depth Information
The rate of reaction can be expressed as
r max C A
K m þ C A
r A ¼
(E17-4.3)
when the reaction rate and concentration of A are evaluated based on the gel volume. The
kinetic parameters are given by r max ¼
2 g/m 3 -gel. To compute
the effectiveness factor, we need both K b and f . From the saturation constant,
0.4 g/(s/m 3 -gel) and K m ¼
K m
C AS
K b ¼
(E17-4.4)
and the Thiele modulus can be computed by Eqn (17.31) or
r
r max
2D eA C AS
Þ 1=2
½1 K b lnð1 þ K 1
d p
6
b
f
¼
(E17-4.5)
1 þ K b
Both K b and f require C AS , which is an unknown that needs to be determined from Eqn
(E17-4.2) . Therefore, iterative scheme is needed to solve the problem.
Since C AS <
1 g/m 3 , we know from Eqn (E17-4.4) that K b >
C Ab ¼
2. We can start the iter-
ative solution by assuming K b / N
. Eqn (E17-4.5) leads to
r
r max
D eA K m
d p
6
f
j K b / N ¼
(E17-4.6)
f
K b /
11.18. From Eqn (17.52) ,
f
cothð3
f
Þ1=3
h
1 ¼
(E17-4.7)
f 2
h ¼
0.08678. With a value of h , we can solve for concentration of nitrate on the gel surface
through Eqn (E17-4.2) ,or
h r max C AS
K m þ C AS V gel ¼ k c a c VðC Ab C AS Þ
(E17-4.8)
r max V gel
k c a c V ¼
0:4 0:2
10 5 6ð1 0:2Þ
1:5 10 3
m 3
m 3 . Eqn (E17-4.8) is reduced to
Let K r ¼
g
=
¼ 2:5
g
=
K r C AS
K m þ C AS ¼ðC Ab C AS Þ
h
(E17-4.8)
which can be solved to give (only the root that is physical is retained):
q
ðC Ab K m
hK r Þ 2 þ 4K m C Ab
C Ab K m
hK r þ
C AS ¼
(E17-4.9)
2
0.93108 g/m 3 .
That is, C AS ¼
Search WWH ::




Custom Search