Biomedical Engineering Reference
In-Depth Information
1
1 þ
f e ¼ k c a K A
h e ¼
r max ;
when K A / N
(17.17b)
1
1 þ
K A þ C Ab
r max
h e ¼
f e ¼
k c a þ K A þ C Ab ;
when f e / N
(17.17c)
which shows a straight line on the log e log plot when mass transfer is limiting. For the case of
K A / N
(i.e. first-order reactions), f e is also known as the Damk¨hler number.
The condition for negligible external mass transfer effects corresponds to low values of f e
as one can observe from Figs 17.2 and 17.3 . One condition normally used is h e >
0.95, i.e. the
external mass transfer contributes to less than 5% reaction rate decrease. Eqn (17.14) can be
used to determine the critical value of the corresponding Thiele modulus. That is,
h e K A
K A
K A þ C Ab
f 1
e
¼
h e þ
h e ÞðK A þ C Ab Þ > 0:95 þ 18:05
(17.18)
ð1
Therefore, the effect of external mass transfer is influenced by the kinetics. When the satura-
tion coefficient K A is larger, the external Thiele modulus is larger for the external mass trans-
fer effects to be negligible.
Example 17-1 Glucose oxidase catalyzes the oxidation of glucose. When glucose is present in
excess, oxygen can be considered the limiting substrate. Michaelis e Menten kinetics may be
applied to describe the oxygen-limited reaction rate. The enzyme is immobilized on the
surface of nonporous glass beads. The particles are of d p ¼
2762 kg/m 3 .
0.001 m, r s ¼
1000 kg $ m 3 , C O 2 b ¼ 0:24
mol $ m 3 .
The medium properties are: m
¼
0.001 Pa $ s, r L ¼
10 9 m 2 /s, and the catalyst loading
The diffusivity of oxygen in the medium is D AB ¼
2.3
10 6 g/glass bead. The volume fraction of glass beads in the reactor is 0.4. The
kinetic constants are: r max ¼
is [E] 0 ¼
10 3 mol-O 2 /(s $ g-enzyme) and K m ¼
0.24 mol $ m 3 . Calcu-
6.5
late the effectiveness factor and the effective rate of reaction assuming
1. no agitation (i.e. diffusion mass transfer);
2. effective medium superficial flow velocity is 1 m/s.
10 3
10 6 /( p
0.001 3 /6) mol-O 2 /m 3 -beads
12.414 mol-O 2 /m 3 -
Solution. r max ¼
6.5
¼
beads.
K b b ¼
K m / C Ab ¼
0.24/0.24
¼
1. For spheres, a
¼
S / V
¼
6/ d p .
1. For pure diffusion to a sphere:
Sh ¼ 2 ¼ k c d p =D AB
(E17-1.1)
10 9 /0.001 m/s
10 6 m/s.
k c ¼
2 D AB / d p ¼
2
2.3
¼
4.6
Thus, from Eqn (17.13)
r max
ðk c aÞðK m þ C Ab Þ ¼
12:414
4:6 10 6 ð6=0:001Þð0:24 þ 0:24Þ ¼ 937:05
f e ¼
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