Biomedical Engineering Reference
In-Depth Information
1
1 þ
f
e
¼ k
c
a
K
A
h
e
¼
r
max
;
when
K
A
/
N
(17.17b)
1
1 þ
K
A
þ C
Ab
r
max
h
e
¼
f
e
¼
k
c
a
þ K
A
þ C
Ab
;
when
f
e
/
N
(17.17c)
which shows a straight line on the log
e
log plot when mass transfer is limiting. For the case of
K
A
/
N
(i.e. first-order reactions),
f
e
is also known as the Damk¨hler number.
The condition for negligible external mass transfer effects corresponds to low values of
f
e
as one can observe from
Figs 17.2 and 17.3
. One condition normally used is
h
e
>
0.95, i.e. the
external mass transfer contributes to less than 5% reaction rate decrease. Eqn
(17.14)
can be
used to determine the critical value of the corresponding Thiele modulus. That is,
h
e
K
A
K
A
K
A
þ C
Ab
f
1
e
¼
h
e
þ
h
e
ÞðK
A
þ C
Ab
Þ
> 0:95 þ 18:05
(17.18)
ð1
Therefore, the effect of external mass transfer is influenced by the kinetics. When the satura-
tion coefficient
K
A
is larger, the external Thiele modulus is larger for the external mass trans-
fer effects to be negligible.
Example 17-1
Glucose oxidase catalyzes the oxidation of glucose. When glucose is present in
excess, oxygen can be considered the limiting substrate. Michaelis
e
Menten kinetics may be
applied to describe the oxygen-limited reaction rate. The enzyme is immobilized on the
surface of nonporous glass beads. The particles are of
d
p
¼
2762 kg/m
3
.
0.001 m,
r
s
¼
1000 kg
$
m
3
,
C
O
2
b
¼ 0:24
mol
$
m
3
.
The medium properties are:
m
¼
0.001 Pa
$
s,
r
L
¼
10
9
m
2
/s, and the catalyst loading
The diffusivity of oxygen in the medium is
D
AB
¼
2.3
10
6
g/glass bead. The volume fraction of glass beads in the reactor is 0.4. The
kinetic constants are:
r
max
¼
is [E]
0
¼
10
3
mol-O
2
/(s
$
g-enzyme) and
K
m
¼
0.24 mol
$
m
3
. Calcu-
6.5
late the effectiveness factor and the effective rate of reaction assuming
1.
no agitation (i.e. diffusion mass transfer);
2.
effective medium superficial flow velocity is 1 m/s.
10
3
10
6
/(
p
0.001
3
/6) mol-O
2
/m
3
-beads
12.414 mol-O
2
/m
3
-
Solution. r
max
¼
6.5
¼
beads.
K
b
b
¼
K
m
/
C
Ab
¼
0.24/0.24
¼
1. For spheres,
a
¼
S
/
V
¼
6/
d
p
.
1.
For pure diffusion to a sphere:
Sh ¼ 2 ¼ k
c
d
p
=D
AB
(E17-1.1)
10
9
/0.001 m/s
10
6
m/s.
k
c
¼
2
D
AB
/
d
p
¼
2
2.3
¼
4.6
Thus, from
Eqn (17.13)
r
max
ðk
c
aÞðK
m
þ C
Ab
Þ
¼
12:414
4:6 10
6
ð6=0:001Þð0:24 þ 0:24Þ
¼ 937:05
f
e
¼
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