Biomedical Engineering Reference
In-Depth Information
Solution:
1. To derive a reasonable rate expression from the simplified pathway given in
Fig. 10.15
c,
we first add some details to the reactions (stoichiometry):
k
1
2
k
1c
M
M
1
þ
E
M
1
$
E
2
þ
E
(E10-2.1)
2
%
2
k
1
k
f1
M
3
þ
E
M
3
$
E
(E10-2.2)
2
%
2
k
f1
k
2
k
2
k
2c
M
M
2
þ
E
M
2
$
E
3
þ
E
(E10-2.3)
3
%
3
/
3
k
3
k
3c
M
M
3
þ
E
M
3
$
E
4
þ
E
(E10-2.4)
4
%
4
/
4
k
3
k
f2
P
1
þ
E
P
1
$
E
(E10-2.5)
4
%
4
k
f2
k
4c
P
M
(E10-2.6)
4
/
1
k
5
k
5
k
5c
M
M
3
þ
E
M
3
$
E
5
þ
E
(E10-2.7)
5
%
5
/
5
k
f3
2
þ
2
$
E
(E10-2.8)
P
E
5
%
P
5
k
f3
k
6c
P
M
(E10-2.9)
5
/
2
We have assumed that the intermediate product M
4
and desired product P
1
are essentially
the same or required no catalyst to proceed. The same holds for M
5
and P
2
. The rate of reac-
tion or rate of generation for species j is given by (Chapter 3),
N
R
r
j
¼
n
ji
r
i
(E10-2.10)
i ¼ 1
where r
j
is the reaction rate for species j, N
R
is the total number of reactions in the system,
n
ji
is the stoichiometric coefficient of species j in the reaction i,andr
i
istherateofreaction
for the reaction i as written. Based on the reaction system described by Eqns
(E10-2.1)
through
(E10-2.9)
, the reaction rates can be written as
r
M
1
¼k
1
½
M
1
½
E
2
þk
1
½
M
E
2
(E10-2.11)
1
r
M
1
E
2
¼ k
1
½
M
1
½
E
2
ðk
1
þ k
1c
Þ½
M
E
2
(E10-2.12)
1
r
M
3
E
2
¼ k
f1
½
3
½
2
k
f1
½
2
(E10-2.13)
M
E
M
3
E
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