Biomedical Engineering Reference
In-Depth Information
Solution:
1. To derive a reasonable rate expression from the simplified pathway given in Fig. 10.15 c,
we first add some details to the reactions (stoichiometry):
k 1
2 k 1c M
M
1 þ
E
M
1 $ E
2 þ
E
(E10-2.1)
2 %
2
k 1
k f1
M
3 þ
E
M
3 $ E
(E10-2.2)
2 %
2
k f1
k 2
k 2
k 2c M
M
2 þ
E
M
2 $ E
3 þ
E
(E10-2.3)
3 %
3 /
3
k 3
k 3c M
M
3 þ
E
M
3 $ E
4 þ
E
(E10-2.4)
4 %
4 /
4
k 3
k f2
P
1 þ
E
P
1 $ E
(E10-2.5)
4 %
4
k f2
k 4c P
M
(E10-2.6)
4 /
1
k 5
k 5
k 5c M
M
3 þ
E
M
3 $ E
5 þ
E
(E10-2.7)
5 %
5 /
5
k f3
2 þ
2 $ E
(E10-2.8)
P
E
5 %
P
5
k f3
k 6c P
M
(E10-2.9)
5 /
2
We have assumed that the intermediate product M 4 and desired product P 1 are essentially
the same or required no catalyst to proceed. The same holds for M 5 and P 2 . The rate of reac-
tion or rate of generation for species j is given by (Chapter 3),
N R
r j ¼
n ji r i
(E10-2.10)
i ¼ 1
where r j is the reaction rate for species j, N R is the total number of reactions in the system,
n ji is the stoichiometric coefficient of species j in the reaction i,andr i istherateofreaction
for the reaction i as written. Based on the reaction system described by Eqns (E10-2.1)
through (E10-2.9) , the reaction rates can be written as
r M 1 ¼k 1 ½
M
1 ½
E
2 þk 1 ½
M
E
2
(E10-2.11)
1
r M 1 E 2 ¼ k 1 ½
M
1 ½
E
2 ðk 1 þ k 1c Þ½
M
E
2
(E10-2.12)
1
r M 3 E 2 ¼ k f1 ½
3 ½
2 k f1 ½
2
(E10-2.13)
M
E
M 3 E
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