Biomedical Engineering Reference
In-Depth Information
Since the final pressures are not functions of temperature for the required conversion of A.
Since based on the rate law,
d
k
f
E
f
RT
2
d
k
b
d
T
¼ k
b
E
b
d
T
¼ k
f
(E5-9.2)
RT
2
We obtain by substituting
Eqn (E5-9.2)
into
Eqn (E5-9.1)
,
RT
2
p
B
p
C
k
b
E
b
E
f
0 ¼ p
A
k
f
(E5-9.3)
RT
2
Therefore,
k
f
p
B
p
C
p
A
E
b
E
f
k
b
¼
(E5-9.4)
For a given conversion
f
A
, the flow rates of the reaction mixture are given by
F
A
¼ F
A
0
1 f
A
;
F
B
¼ F
A
0
f
A
¼ F
C
;
and
F
T
¼ F
A
þ F
B
þ F
C
¼ F
A0
1 þ f
A
:
Therefore, the partial pressures in the final reaction mixture are given by
F
A
F
T
P ¼
1 f
A
1 þ f
A
P
p
A
¼
(E5-9.5a)
F
B
F
T
P ¼
f
A
1 þ f
A
P ¼ p
C
p
B
¼
(E5-9.5b)
Substitute
Eqn (E5-9.5)
into
Eqn (E5-9.4)
, we obtain
f
A
0:22
2
ð1 þ 0:22Þð1 0:22Þ
k
f
k
b
¼
E
b
E
f
P ¼
60
20
50
bar
1 þ f
A
1 f
A
¼ 7:63
bar
Also
0:435 exp
E
f
R
T
exp
E
b
E
f
R
T
bar
k
f
k
b
¼
0
:
435
147
147 exp
bar
¼
E
b
R
T
Therefore,
E
b
E
f
60000 20000
8:314 ln
147
0:435
7:63
T ¼
R ln
k
f
bar
1
¼
K
¼ 614:8
K
147
0:435
k
b
Now we have obtained the optimum temperature (for maximum reaction rate). Substitute
the temperature and partial pressures into the rate expression, we obtain the maximum reac-
tion rate
=
m
3
: s
r ¼ 0:183
mol
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