Biomedical Engineering Reference
In-Depth Information
t
= 0, C A =C A0 ,
C B = 0,
C C = 0
A
B
C
A,
B,
C
t
=
t
,C A ,
C B ,
C C
FIGURE E4-3.1 A schematic diagram of the batch reactor.
Solution. This is a set of two reactions occurring in series. Figure E4-3.1 shows a sketch of the
reactor system. Mole balance for species j leads to
d
n j
d
t ¼ r j V
(E4-3.1)
Since the volume is constant, we have
d C j
d
¼ r j
(E4-3.2)
t
We next find the rates of reaction. Applying Eqn (3.66), we obtain
r A ¼ n 1A r 1 þ n 2A r 2
¼r 1 ¼ k 1 C A
(E4-3.3)
r B ¼ n 1B r 1 þ n 2B r 2
¼ r 1 r 2 ¼ k 1 C A k 2 C B
(E4-3.4)
r C ¼ n 1C r 1 þ n 2C r 2
¼ r 2 ¼ k 2 C B
(E4-3.5)
Substituting Eqn (E4-3.3) into Eqn (E4-3.2) , we obtain
d C A
d
¼ r A ¼k 1 C A
(E4-3.6)
t
Separation of variables and integration,
Z C A
Z t
d C A
C A
¼
k 1 d
t
(E4-3.7)
C A0
0
We obtain
ln C A
C A0 ¼k 1 t
(E4-3.8)
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