Biomedical Engineering Reference
In-Depth Information
t
= 0, C
A
=C
A0
,
C
B
= 0,
C
C
= 0
A
B
C
A,
B,
C
t
=
t
,C
A
,
C
B
,
C
C
FIGURE E4-3.1
A schematic diagram of the batch reactor.
Solution. This is a set of two reactions occurring in series.
Figure E4-3.1
shows a sketch of the
reactor system. Mole balance for species
j
leads to
d
n
j
d
t
¼ r
j
V
(E4-3.1)
Since the volume is constant, we have
d
C
j
d
¼ r
j
(E4-3.2)
t
We next find the rates of reaction. Applying Eqn (3.66), we obtain
r
A
¼ n
1A
r
1
þ n
2A
r
2
¼r
1
¼ k
1
C
A
(E4-3.3)
r
B
¼ n
1B
r
1
þ n
2B
r
2
¼ r
1
r
2
¼ k
1
C
A
k
2
C
B
(E4-3.4)
r
C
¼ n
1C
r
1
þ n
2C
r
2
¼ r
2
¼ k
2
C
B
(E4-3.5)
Substituting Eqn
(E4-3.3)
into Eqn
(E4-3.2)
, we obtain
d
C
A
d
¼ r
A
¼k
1
C
A
(E4-3.6)
t
Separation of variables and integration,
Z
C
A
Z
t
d
C
A
C
A
¼
k
1
d
t
(E4-3.7)
C
A0
0
We obtain
ln
C
A
C
A0
¼k
1
t
(E4-3.8)
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