Biomedical Engineering Reference
In-Depth Information
C
2
C
2
H
5
OH: m
EtOH
(5%)
C
6
H
10
O
5
: 2 kg
C
6
H
10
O
5
:
H
2
O: 2 kg
H
2
O:
Yeast:
Yeast: 10 g
FIGURE E3-5
Schematic diagram showing the control volume or system of interest for mass balance.
To produce 1 mol of alcohol, 1 mol of CO
2
is also produced and released, while half a mole of
glucose-equivalent of starch is consumed.
46:07
:
m
EtOH
¼ 44:01
:
m
CO
2
m
EtOH
46:07
m
CO
2
¼ 44:01
¼
44:01
46:07
m
EtOH
Overall mass balance, Eqn
(3.96)
:
0
0
In - Out + Generation = Accumulation
Which leads to: m
0
¼
2
þ
2
þ
0.01 kg
¼
In
¼
Out
¼
m
CO
2
þ
m
mix
Therefore:
m
CO
2
¼ 4:01
44:01
m
mix
¼
m
0
m
EtOH
46:07
We also know that
m
EtOH
m
mix
5
%
¼ u
EtOH
¼
It then leads to:
m
EtOH
u
EtOH
¼
0
44:01
46:07
m
m
EtOH
Solve for m
EtOH
, we obtain
0
u
EtOH
1 þ
44:01
46:07
m
4:01 0:05
1 þ
44:01
m
EtOH
¼
u
EtOH
¼
kg
¼ 0:1914
kg
46:07
0:05
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