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k r = 1
r 2 = constant ,
Δ ln λ r + 2
r 2 λ r =0 , λ r =cosh 2 ( q/r ) , ln λ r =
2lncosh( q/r ) ,
(1.220)
2
2
r 2
1
cosh 2 ( q/r )
D q ln λ r =
r tanh( q/r )) , Δ r ln λ r = D qq ln λ r =
2
r 2 λ r
q. e. d.
Left differential equation of the factor of conformality (
=
2
A 1 ,A 1 ,A 2
E
):
k l = (1 E 2 sin 2 φ ) 2
= 1 E 2 sin 2 f 1 ( Q/A 1 )
,
A 1 (1
A 1 (1
E 2 )
E 2 )
cos 2 f 1 ( Q/A 1 )
Δ ln λ l +2 k ( Q ) λ l =0 , λ l =
1 − E 2 sin 2 f 1 ( Q/A 1 )
,
(1.221)
1
ln λ l =2ln f 1 ( Q/A 1 )
2 ln[1 − E 2 sin 2 f 1 ( Q/A 1 )] ,
Δ l ln λ l = D QQ ln λ l =
2 k ( Q ) λ l
q.e.d .
In Box 1.27 , we write down the metric forms “left d S 2 ” and “right d s 2 ” in the initial coordinates
{
E 2 sin 2 Φ ) and (ii) cos 2 φ .
The first term A 1 d Λ and r d λ , respectively, generates d P and d p , respectively. In contrast, the
second term ([ A 1 (1
, respectively. Second, we factorize by (i) cos 2 Φ/ (1
Λ, Φ
}
and
{
λ, φ
}
E 2 sin 2 Φ )] cos Φ )d Φ and ( r/ cos φ )d φ , respectively, generates d Q
and d q , respectively. Indeed, the first factors cos 2 Φ/ (1
E 2 ) / (1
E 2 sin 2 Φ )andcos 2 φ produce the left
and the right factor of conformality, called λ l and λ r , respectively. They are reciprocal to Λ l and
Λ r , respectively. Third, by means of Box 1.28 , we aim at representing the factors of conformality,
λ l and λ r , in terms of conformal (isometric, isothermal) latitude Q and q , respectively, namely
λ l ( Q )and λ r ( q ), respectively. Here, we have to invert the functions Q/A 1 = f ( Φ )and q/r =
ln tan( π/ 4+ φ/ 2) = artanh (sin φ ), also called the inverse Lambert or Gudermann function , lam or
gd, respectively, φ =lam( q/r )=gd( q/r )orsin φ = tanh(q/r), cos φ =1 / cosh(q / r). While λ l ( Q )
and Λ l ( Q ) cannot be given in a closed form, λ r =1 / cosh 2 ( q/r )and Λ r =cosh 2 ( q/r ) are available
in a simple form. Fourth, by means of Box 1.29 , we prove that λ r and λ l , respectively, fulfill the
conformal representation of the right and the left Gaussian curvature, here written in two versions
as a special Helmholtz differential equation. For being simpler, we did first “right” followed by
the more complex “left” computation. Indeed, for given Gaussian curvature k r =1 /r 2 = constant
of the sphere
2
E 2 sin 2 Φ ) 2 / [ A 1 (1
E 2 )] of the ellipsoid-of-revolution
2
A 1 ,A 1 ,A 2
S
r and k l =(1
E
finally transformed into
coordinates of type conformal (isometric, isothermal), we succeed
to prove Δ ln λ 2 +2 2 = 0 of type “right” and “left”.
{
q,Q
}
Solution (the fourth problem).
2
2
A “simple conformal mapping” of
E
A 1 ,A 1 ,A 2 S
r is the isoparametric mapping characterized by
 
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