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or
L ( x 1 ,x 2 ,x 3 ,x 4 ):=( X − x 1 ) 2 +( Y − x 2 ) 2 +( Z − x 3 ) 2
+ x 4 ( A 2 [( x 1 ) 2 +( x 2 ) 2 ]+ A 1 ( x 3 ) 2
A 1 A 2 ) ,
(iv)
2 + Λ ( x 1 ) 2
A 1
1
+ ( x 2 ) 2
A 2
+ ( x 3 ) 2
( x 1 ,x 2 ,x 3 ,x 4 ):=
L
X
x
A 3
(J.8)
( x 1 ,x 2 ,x 3 ,x 4 ):=
2 + x 4 [ A 2 A 3 x 2 + A 1 A 3 y 2 + A 1 A 2 z 2
L
X
x
A 1 A 2 A 3 ] .
First variation:
∂L
∂x μ ( x ν )=0 ∀ μ, ν ∈{ 1 , 2 , 3 , 4 }
(J.9)
⇐⇒
(i) plane
2 :
P
x 1 )+ a 1 x 4 =0 ,
x 2 )+ a 2 x 4 =0 ,
x 3 )+ a 3 x 4 =0 ,
( X
( Y
( Z
(J.10)
a 1 x 1 + a 2 x 2 + a 3 x 3 + a 4 =0;
(ii) sphere S
2
r :
( X − x 1 )+ x 1 x 4 =0 , − ( Y − x 2 )+ x 2 x 4 =0 , − ( Z − x 3 )+ x 3 x 4 =0 ,
(J.11)
r 2 =0;
(iii) ellipsoid-of-revolution
( x 1 ) 2 +( x 2 ) 2 +( x 3 ) 2
2
A 1 ,A 2
E
:
x 1) + A 2 x 1 x 4 =0 ,
x 2 )+ A 2 x 2 x 4 =0 ,
x 3 )
( X
( Y
( Z
+ A 1 x 3 x 4 =0 ,
(J.12)
A 2 [( x 1 ) 2 +( x 2 ) 2 ]+ A 1 ( x 3 ) 2
A 1 A 2 =0;
2
(iv) triaxial ellipsoid E
A 1 ,A 2 ,A 2 :
x 1 )+ A 2 A 3 x 1 x 4 =0 ,
x 2 )+ A 1 A 3 x 2 x 4 =0 ,
x 3 )
( X
( Y
( Z
+ A 1 A 2 x 3 x 4 =0 ,
(J.13)
A 2 A 3 ( x 1 ) 2 + A 1 A 3 ( x 2 ) 2 + A 1 A 2 ( x 3 ) 2
− A 1 A 2 A 3 =0 .
Second variation.
The second variation decides about the solution of type “minimum” or
“maximum” or “turning point”.
In our case
2
1
2
L
∂x k ∂x l ( x γ ) > 0
(J.14)
⇐⇒
+1 0 0
0+10
00+1
> 0;
2 :
(i) plane P
(J.15)
 
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