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(ii)
If the relative eccentricity vanishes,
E
= 0, then we arrive at the Hammer projection of the sphere
S
A
1
,namely
x
=
c
1
r
(
Λ, Φ
;
c
3
,c
4
)cos
α
(
Λ, Φ
;
c
3
,c
4
)
,
y
=
c
2
r
(
Λ, Φ
;
c
3
,c
4
)sin
α
(
Λ, Φ
;
c
3
,c
4
)
,
(H.83)
subject to
1
c
4
sin
2
Φ
sin
c
3
Λ
−
cos
α
(
Λ, Φ
;
c
3
,c
4
)=
1
,
(H.84)
c
4
sin
2
Φ
)cos
2
c
3
Λ
−
(1
−
c
4
sin
Φ
1
−
(1
− c
4
sin
2
Φ
)cos
2
c
3
Λ
sin
α
(
Λ, Φ
;
c
3
,c
4
)=
,
(H.85)
r
=
A
1
√
2
1
−
1
− c
4
sin
2
Φ
cos
c
3
Λ,
(H.86)
1
− c
4
sin
2
Φ
sin
c
3
Λ
x
=
c
1
A
1
√
2
1+
1
,
(H.87)
c
4
sin
2
Φ
cos
c
3
Λ
−
y
=
c
2
A
1
√
2
c
4
sin
Φ
1+
1
.
(H.88)
c
4
sin
2
Φ
cos
c
3
Λ
−
(iii)
If we choose
c
1
=2
,c
2
=1
,c
3
=1
/
2, and
c
4
= 1 which fulfills
c
1
c
2
c
3
c
4
= 1 (Hammer's choice),
then the mapping of the right biaxial ellipsoid
2
A
1
,A
2
E
with respect to left biaxial ellipsoid
E
A
1
∗
,A
2
∗
subject to
A
1
∗
=
A
1
,A
2
∗
=
A
2
onto the transverse tangent plane being normal to
E
3
and rescaled,
namely of equiareal type, reduces to
x
=2
r
(
Λ, Φ
)cos
α
(
Λ, Φ
)
, y
=
r
(
Λ, Φ
)sin
α
(
Λ, Φ
)
,
(H.89)
sin
Λ/
2
sin
2
Λ/
2+(1
cos
α
(
Λ, Φ
)=
E
2
)
2
tan
2
Φ
,
(H.90)
−
E
2
)tan
Φ
(1
−
sin
2
Λ/
2+(1
sin
α
(
Λ, Φ
)=
E
2
)
2
tan
2
Φ
,
−
sin
2
Λ/
2cos
2
Φ
+(1
E
2
)
2
sin
2
Φ
−
r
2
(
Λ, Φ
)=
A
1
E
2
)sin
2
Φ
)
3
/
2
(
t
1
+
t
2
+
t
3
+
t
4
)
,
(H.91)
(sin
2
Λ/
2cos
2
Φ
+(1
−
sin
2
Λ/
2cos
2
Φ
+(1
cos
Λ/
2cos
Φ
1
− E
2
sin
2
Φ
t
1
=
E
2
)sin
2
Φ,
−
−
cos
2
Λ/
2cos
2
Φ
E
2
sin
Φ
1
−
E
sin
Φ
cos
Φ
cos
Λ/
2
(1
− E
2
sin
2
Φ
)(1
−
cos
2
Λ/
2cos
2
Φ
)
t
2
=
−
arcsin
,
(H.92)
t
3
=
sin
2
Λ/
2cos
2
Φ
+(1
− E
2
)sin
2
Φ,
cos
2
Λ/
2cos
2
Φ
E
sin
Φ
t
4
=
1
−
E
sin
Φ
arcsin
1
cos
2
Λ/
2cos
2
Φ
.
−
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