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(ii)
If the relative eccentricity vanishes, E = 0, then we arrive at the Hammer projection of the sphere
S
A 1
,namely
x = c 1 r ( Λ, Φ ; c 3 ,c 4 )cos α ( Λ, Φ ; c 3 ,c 4 ) ,
y = c 2 r ( Λ, Φ ; c 3 ,c 4 )sin α ( Λ, Φ ; c 3 ,c 4 ) ,
(H.83)
subject to
1
c 4 sin 2 Φ sin c 3 Λ
cos α ( Λ, Φ ; c 3 ,c 4 )=
1
,
(H.84)
c 4 sin 2 Φ )cos 2 c 3 Λ
(1
c 4 sin Φ
1 (1 − c 4 sin 2 Φ )cos 2 c 3 Λ
sin α ( Λ, Φ ; c 3 ,c 4 )=
,
(H.85)
r = A 1 2 1
1 − c 4 sin 2 Φ cos c 3 Λ,
(H.86)
1 − c 4 sin 2 Φ sin c 3 Λ
x = c 1 A 1 2
1+ 1
,
(H.87)
c 4 sin 2 Φ cos c 3 Λ
y = c 2 A 1 2
c 4 sin Φ
1+ 1
.
(H.88)
c 4 sin 2 Φ cos c 3 Λ
(iii)
If we choose c 1 =2 ,c 2 =1 ,c 3 =1 / 2, and c 4 = 1 which fulfills c 1 c 2 c 3 c 4 = 1 (Hammer's choice),
then the mapping of the right biaxial ellipsoid
2
A 1 ,A 2
E
with respect to left biaxial ellipsoid
E
A 1 ,A 2
subject to A 1 = A 1 ,A 2 = A 2 onto the transverse tangent plane being normal to E 3 and rescaled,
namely of equiareal type, reduces to
x =2 r ( Λ, Φ )cos α ( Λ, Φ ) , y = r ( Λ, Φ )sin α ( Λ, Φ ) ,
(H.89)
sin Λ/ 2
sin 2 Λ/ 2+(1
cos α ( Λ, Φ )=
E 2 ) 2 tan 2 Φ ,
(H.90)
E 2 )tan Φ
(1
sin 2 Λ/ 2+(1
sin α ( Λ, Φ )=
E 2 ) 2 tan 2 Φ ,
sin 2 Λ/ 2cos 2 Φ +(1
E 2 ) 2 sin 2 Φ
r 2 ( Λ, Φ )= A 1
E 2 )sin 2 Φ ) 3 / 2 ( t 1 + t 2 + t 3 + t 4 ) ,
(H.91)
(sin 2 Λ/ 2cos 2 Φ +(1
sin 2 Λ/ 2cos 2 Φ +(1
cos Λ/ 2cos Φ
1 − E 2 sin 2 Φ
t 1 =
E 2 )sin 2 Φ,
cos 2 Λ/ 2cos 2 Φ
E 2 sin Φ
1
E sin Φ cos Φ cos Λ/ 2
(1 − E 2 sin 2 Φ )(1 cos 2 Λ/ 2cos 2 Φ )
t 2 =
arcsin
,
(H.92)
t 3 = sin 2 Λ/ 2cos 2 Φ +(1 − E 2 )sin 2 Φ,
cos 2 Λ/ 2cos 2 Φ
E sin Φ
t 4 = 1
E sin Φ
arcsin
1
cos 2 Λ/ 2cos 2 Φ .
 
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