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g 22
1
G 11 G 22 − G 12
g 11 x 2 .
The converse (iv) (ii) is obvious.
x 1 =G l A
End of Proof (third part).
Here is the remark relating to G l being diagonal, not unity, of course. An obvious generalization
for solving ( γ )and( δ )for g 12
= 0 would be the
“Ansatz x 1 =G l X x 2 , X= yx
,
(1.168)
x
y
the superposition of a diagonal trace-free matrix diag [ y,
y ] and an antisymmetric matrix Ax.
Indeed, we succeed in determining the unknowns x and y according to the above steps, but fail
to arrive at linear relations between the partials
{
u U ,u V ,v U ,v V }
.
M l M l
Fig. 1.24. Flow chart, conformal mapping
r has been chosen.
In Fig. 1.24 , the alternative path of generating a conformal mapping from a left curved surface
to a right curved surface is outlined. First, the original coordinates
In practice, a different way in constructing a conformeomorphism M
l
M
{
U 1 ,U 2
}
or
{
U, V
}
,which
parameterize the left surface, are transformed to alternative left conformal coordinates
{
P,Q
}
.
d S 2 =
Λ 2 (d P 2 +d Q 2 ) is described by identical metric coecients G PP = G QQ = Λ 2 and G PQ =0.
which are also called isometric or isothermal . Indeed, the left differential invariant I l
 
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