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g
22
1
G
11
G
22
− G
12
⇒
g
11
x
2
.
The converse (iv)
⇒
(ii) is obvious.
x
1
=G
l
A
End of Proof (third part).
Here is the remark relating to G
l
being diagonal, not unity, of course. An obvious generalization
for solving (
γ
)and(
δ
)for
g
12
= 0 would be the
“Ansatz
x
1
=G
l
X
x
2
,
X=
yx
,
(1.168)
−
x
−
y
the superposition of a diagonal trace-free matrix diag [
y,
y
] and an antisymmetric matrix Ax.
Indeed, we succeed in determining the unknowns
x
and
y
according to the above steps, but fail
to arrive at linear relations between the partials
−
{
u
U
,u
V
,v
U
,v
V
}
.
M
l
→
M
l
Fig. 1.24.
Flow chart, conformal mapping
r
has been chosen.
In Fig.
1.24
, the alternative path of generating a conformal mapping from a left curved surface
to a right curved surface is outlined. First, the original coordinates
In practice, a different way in constructing a conformeomorphism
M
l
→
M
{
U
1
,U
2
}
or
{
U, V
}
,which
parameterize the left surface, are transformed to alternative left
conformal coordinates
{
P,Q
}
.
d
S
2
=
Λ
2
(d
P
2
+d
Q
2
) is described by identical metric coecients
G
PP
=
G
QQ
=
Λ
2
and
G
PQ
=0.
which are also called
isometric
or
isothermal
. Indeed, the left differential invariant
I
l
∼
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