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Definition 1.10 (Conformal mapping).
2
l
2
r is called angle preserving conformal
mapping (conformeomorphism, inner product preserving) if Ψ l = Ψ r and Σ l = Σ =0
An orientation preserving diffeomorphism f :
M
M
Σ r = σ =
2
2
0 for all points of
M
l and
M
r , respectively, holds.
End of Definition.
2
l
2
Theorem 1.11 (Conformeomorphism
M
M
r , conformal mapping).
2
l
2
Let f :
r be an orientation preserving conformal mapping. Then the following conditions
(i)-(iv) are equivalent:
M
M
(i) Ψ l ( U 1 , U 2 )= Ψ r ( u 1 , u 2 ) ,
(1.153)
U 1 , U 2
, respectively;
(ii) C l = Λ 2 ( U 0 )G l , C l G l = Λ 2 ( U 0 )I 2 versus C r = λ 2 ( u 0 )G r , C r G r = λ 2 ( u 0 )I 2 ,
(1.154)
for all tangent vectors
{
}
and their images
{
u 1 , u 2
}
E l = K ( U 0 )G l , E l G l = K ( U 0 )I 2 versus E r = κ ( u 0 )G r , E r G r = κ ( u 0 )I 2 ;
(iii) K =( Λ 2
1) / 2= κ, 2 κ +1= λ 2 ,
Λ 1 = Λ 2 = Λ ( U 0 ) sus λ 1 = λ 2 = λ ( u 0 ) ,
K 1 = K 2 = K ( U 0 )versus κ 1 = κ 2 = κ ( u 0 ) ,
1) / 2 2 =2 K +1versus( λ 2
(1.155)
Λ 2 ( U 0 )= 1
2 tr[C l G i ] sus λ 2 ( u 0 )= 1
2 tr[C r G r ];
left dilatation:
right dilatation:
K = 1
2 tr[E l G l ] sus κ = 1
2 tr[E r G r ] ,
tr[C l G l ]=2 det[C l G l ] versus tr[C r G r ]=2 det[C r G r ] ,
(1.156)
tr[E l G l ]=2 det[E l G l ] versus tr[E r G r ]=2 det[E r G r ] ,
(iv) generalized Korn-Lichtenstein equations (special case: g 12 =0):
u U
u V
=
g 11
g 22
−G 12 G 11
−G 22 G 12
v U
v V
,
1
G 11 G 22
(1.157)
G 12
subject to the integrability conditions u UV = u VU and v UV = v VU .
End of Theorem.
Before we present the sketches of proofs for the various conditions, it has to be noted that the
generalized Korn-Lichtenstein equations, which govern conformal mapping
r ,sufferfrom
the defect that they contain the unknown functions g 11 [ u λ ( U A )] and g 22 [ u λ ( U Λ )], and the reason
is that the mapping functions u λ ( U Λ ) have to be determined. In case of
2
l
M
M
r ,g μν
2 μν
,
the corresponding Korn-Lichtenstein equations do not suffer since these functions do not appear.
The stated problem is overcome by representing the right Riemann manifold M
{ M
}
=
{ R
}
r by isometric
 
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