Geography Reference
In-Depth Information
a
cos
B
120(1
− e
2
)
3
1
− e
2
sin
2
B
×
−
a
5
=
5+28sin
2
B
24 sin
4
B
+
e
2
(1 + 16 sin
2
B
86 sin
4
B
+72sin
6
B
)+
×
[
−
−
−
+
e
4
sin
4
B
(
26 + 100 sin
2
B
77 sin
4
B
)+
e
6
sin
6
B
(12
39 sin
2
B
+28sin
4
B
)]
.
−
−
−
Solution of the boundary value problem.
Let us consider the boundary value problem for the d'Alembert-Euler equations (Cauchy-
Riemann equations) subject to the integrability conditions of harmonicity type, namely (
D.72
)
and (
D.73
), in the function space of polynomial type (
D.74
)and(
D.75
). Once we compare the
boundary conditions in the base
{q
r−
2
s
p
2
s
,q
r−
2
s
+1
p
2
s−
1
}
,weareledto(
D.76
).
x
p
=
y
q
,x
q
=
−y
p
,
Δx
=
x
pp
+
x
qq
=0
,Δy
=
y
pp
+
y
qq
=0
.
(D.72)
x
(0
,q
)=
∞
a
r
q
r
,y
(0
,q
)=0
,
(D.73)
r
=0
x
(
p, q
)=
α
0
+
α
1
q
+
β
1
p
+
α
2
(
q
2
p
2
)+2
β
2
qp
+
−
(
−
1)
s
r
q
r−
2
s
p
2
s
+
(
−
1)
s
+1
r
2
s
q
r−
2
s
+1
p
2
s−
1
,
[
r/
2]
[(
r
+1)
/
2]
N
N
+
α
r
β
r
(D.74)
2
s
−
1
r
=3
s
=0
r
=3
s
=1
β
2
(
q
2
p
2
)+2
α
2
qp
y
(
p, q
)=
β
0
−
β
1
q
+
α
1
p
−
−
−
1)
s
r
q
r−
2
s
p
2
s
+
1)
s
+1
r
q
r−
2
s
+1
p
2
s−
1
,
[
r/
2]
[(
r
+1)
/
2]
N
N
−
β
r
(
−
α
r
(
−
(D.75)
2
s
2
s −
1
r
=3
s
=0
r
=3
s
=1
α
r
=
a
r
(
B
0
)
,β
r
=0
∀ r
=0
,...,∞.
(D.76)
End of Example.
a,b
, universal transverse Mercator projection modulo unknown dilatation param-
eter, c:c:cha-cha-cha).
Corollary D.5 (
E
The solution of the boundary value problem, where the
L
0
meta-equator is modulo a dilatation
parameter
equidistantly mapped, is given by (
D.77
), (
D.78
), and the
a
r
of Table
D.1
.
⎡
q
r−
2
s
p
2
s
⎤
(
−
1)
s
r
[
r/
2]
N
⎣
a
0
+
a
1
q
+
a
2
(
q
2
⎦
,
− p
2
)+
x
(
p, q
)=
a
r
(D.77)
2
s
r
=3
s
=0
⎡
q
r−
2
s
p
2
s−
1
⎤
1)
s
+1
r
[(
r
+1)
/
2]
N
⎣
a
1
p
+2
a
2
qp
+
⎦
.
y
(
p, q
)=
a
r
(
−
(D.78)
2
s
−
1
r
=3
s
=1
Search WWH ::
Custom Search