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(ii) equiareal:
(1 + 4
V
2
)
3
/
2
−
1
x
=
cos (
nU
)
6
n
(1 + 4
V
2
)
3
/
2
−
1
y
=
sin (
nU
)
6
n
(1 + 4
V
2
)
3
/
2
(1 + 4
V
2
)
3
/
2
Λ
1
=
n
−
1
,Λ
2
=
V
−
1
V
6
n
n
6
n
(iii) equidistant:
2
V
√
1+4
V
2
+
1
x
=(
1
4
arcsinh
2
V
)cos(
nU
)
2
V
√
1+4
V
2
+
1
y=(
1
4
arcsinh
2
V
) sin (
nU
)
2
n
√
1+4
V
2
+
Λ
1
=
1
n
4
V
arcsinh
(2
V
)
,Λ
2
=1
P
2
onto a developed cylinder
C
1
Fig. 23.16.
Conformal mapping of
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