Geography Reference
In-Depth Information
(ii) equiareal:
(1 + 4 V 2 ) 3 / 2
1
x =
cos ( nU )
6 n
(1 + 4 V 2 ) 3 / 2
1
y =
sin ( nU )
6 n
(1 + 4 V 2 ) 3 / 2
(1 + 4 V 2 ) 3 / 2
Λ 1 = n
1
2 = V
1
V
6 n
n
6 n
(iii) equidistant:
2 V 1+4 V 2 + 1
x =( 1
4 arcsinh 2 V )cos( nU )
2 V 1+4 V 2 + 1
y=( 1
4 arcsinh 2 V ) sin ( nU )
2 n 1+4 V 2 +
Λ 1 = 1
n
4 V arcsinh (2 V ) 2 =1
P 2 onto a developed cylinder
C 1
Fig. 23.16. Conformal mapping of
 
Search WWH ::




Custom Search