Geography Reference
In-Depth Information
√
1+
tanh
2
x
1
−tanh
2
x
=1+
2
tanh
2
x
+
1
8
tanh
4
x
+
2
16
tanh
6
x
+
O
8
(
tanhx
)
∀|
(23.37)
tanhx
|
<
1
tanh
2
xdx
=
3
2
3
2
tanhx
+
3
−
2
x
(23.38)
tanh
4
xdx
=
11
8
11
11
8
tanhx
+
11
24
tanh
3
x
−
−
8
x
(23.39)
tanh
6
xdx
=
23
16
23
23
23
16
tanhx
+
23
80
tanh
5
x
48
tanh
3
x
−
−
−
16
x
(23.40)
1
tanh
2
x
−
1
1+
tanh
2
xdx
=
x
1+
3
2
+
11
8
+
23
−
−
tanh
x
·
16
3
− tanh
3
x
11
2
+
11
8
+
23
24
+
23
23
80
tanh
5
x
+
O
7
(
tanhx
)
−
(23.41)
16
48
2
:=
2
onto the
Box 23.14 (Equidistant mapping of the rotational symmetric hyperboloid
M
H
2
circular cylinder
C
1
).
f
=
√
cosh 2
V
=
1+
tan
h
2
V/
1
tanh
2
V
Λ
2
(
V
)=1
∀
V
→
−
(23.42)
f
(
V
)=
1+
tanh
2
V
1
− tanh
2
V
dV
+
c
(23.43)
f
(0) = 0 =
c
→
(23.44)
1
1
3
tanh
3
V
10
tanh
5
V
+
O
7
(
tanhV
)
f
(
V
)=3
V
−
2
tanhV
−
−
(23.45)
Box 23.15 (The integral
√
1+
tanh
2
x
√
1
−tanh
2
x
dx
).
x
2
−
1
/
2
√
1+
x
2
=1+
x
2
+
1
1
2
x
4
+
1
2
x
6
+
O
8
(
x
)
−
∀|
x
|
<
1
(23.46)
√
1+
tanh
2
x
√
1
−tanh
2
x
=1+
tanh
2
x
+
2
tanh
4
x
+
2
tanh
6
x
+
O
8
(tanh
x
)
∀|
(23.47)
tanhx
|
<
1
tanh
2
xdx
=
−
tanh
x
+
x
(23.48)
tanh
4
xdx
=
1
2
1
1
2
tanhx
+
1
6
tanh
3
x
−
−
2
x
(23.49)
tanh
6
xdx
=
−
1
2
1
1
1
2
tanhx
+
1
10
tanh
5
x −
6
tanh
3
x −
2
x
(23.50)
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