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Table 22.15 Polynomial representation series expansion: y ( q )= h =0
γ h q h + O ( N +1)
N =5
E 2 B 0
0
γ 0 = A 1 1
dB
( Table 22.12 )
(22.91)
E 2 sin 2 B ) 3 / 2
(1
A 1 cos B 0
A 1 cos lam 1 Q 0
γ 1 =
1
=
1
(22.92)
E 2 sin 2 B 0
E 2 sin 2 lam 1 Q 0
A 1 cos B 0 sin B 0
2 1
γ 2 =
(22.93)
E 2 sin 2 B 0
A 1 cos B 0 1
2 sin 2 B 0 + E 2 sin 4 B 0
E 2 ) 1
γ 3 =
(22.94)
6(1
E 2 sin 2 B 0
A 1 cosB 0 sin B 0
6 sin 2 B 0
E 2 (1 + 6 sin 2 B 0
γ 4 =
E 2 ) 1
[5
24 (1
2 sin 2 B 0
9 sin 4 B 0 )+ E 4 sin 4 B 0 3
4 sin 2 B 0 ]
(22.95)
A 1 cos B 0
5+28 sin 2 B 0
24 sin 4 B 0 +
γ 5 =
E 2 ) 3 1
[
120 (1
E 2 sin 2 B 0
+ E 2 1+16 sin 2 B 0
86 sin 4 B 0 +72 sin 6 B 0 + E 4 sin 4 B 0 (
26 + +100 sin 2 B 0
77 sin 4 B 0 )+ E 6 sin 6 B 0 12
39 sin 2 B 0 +28 sin 4 B 0 ]
(22.96)
tion y ( b, l ) is given in Table 22.18 ,Eq.( 22.114 ), “ b -representation” subject to the coecients
{
y 10 ,y 20 ,y 02 ,y 30 ,y 12 ,y 40 ,y 22 ,y 04 ,y 50 ,y 32 ,y 14 ,
}
of Table 22.19 .
22-34 The Second Boundary Condition or the Arc Preserving
Mapping of the Reference Parallel
Up to now we only succeeded to determine the Northern harmonic map y = η ( q,l )interms
of relative isometric coordinates ( q,l )of Mercator type or y = y ( b, l ) in terms of relative Gauss
ellipsoidal coordinates ( b, l ). By means of the second boundary condition we shall be able to
determine the Eastern harmonic map x = ξ ( q,l ) or x = x ( b, l ): The parallel circle also called
small circle ” which passes the Taylor point ( Q 0 ,L 0 )or( B 0 ,L 0 ) will be mapped according to its
length (Table 22.20 ).
Indeed by means of Table 22.10 ,Eqs.( 22.127 )-( 22.129 ), we have succeeded to compute such
an arc length of a small circle from L 0 to L , the solution of the second boundary value problem.
(i) Δx = 0 (region operator)
(ii) x (0 ,l )= β 1 l
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