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Detailed Examples 22.1 and 22.2 follow to illustrate homogeneous polynomial of degree 2 and
3 under the Laplace-Beltrami harmonicity condition and the recurrence relations fixed to initial
data ξ 20 =1 30 =1.
Example 22.1 (homogenous polynomial of degree 2: POLY ξ ( q,l ;1)= ξ 2 , 0 q 2 + ξ 1 , 1 ql + ξ 0 , 2 l 2 ).
1st derivatives:
D q POLY ( q,l ;2)=2 ξ 2 , 0 q + ξ 1 , 1 ,D l POLY ( q,l, ;2)=2 ξ 2 , 0 l + ξ 1 , 1 q
2nd derivatives:
D q POLY ( q,l ;2)=2 ξ 2 , 0 , D l POLY ( q,l, ;2)=2 ξ 0 , 2
ΔPOLY ξ ( q,l ;2)=0 ↔ ξ 2 , 0 + ξ 0 , 2 =0
End of Example.
Corollary ( POLY ξ ( q,l ;)).
Given a harmonic polynomial POLY ξ ( q,l ;2) of degree 2. If ξ 2 , 0 =1then ξ 0 , 2 =
1. ξ 1 , 1 is left
undermined. If ξ 2 , 0 =1 0 , 2 =
1 1 , 1 =2then
POLY ξ ( q,l ;2)= q 2
l 2 +2 ql
End of Corollary.
Example 22.2 (homogenous polynomial of degree 3: POLY ξ ( q,l ;3)= ξ 3 , 0 q 3 + ξ 2 , 1 q 2 l + ξ 1 , 2 ql 2 +
ξ 0 , 3 l 3 ).
1st derivatives
D q POLY ξ ( q.l ;3)=3 ξ 3 , 0 q 2 +2 ξ 2 , 1 ql + ξ 1 , 2 l 2
D l POLY ξ ( q,l, ;3)= ξ 2 , 1 q 2 +2 ξ 1 , 2 ql +3 ξ 0 , 3 l 2
2nd derivatives
D q POLY ξ ( q,l ;3)=3 × 2 ξ 3 , 0 q +2 ξ 2 , 1 l
D l POLY ξ ( q,l ;3)=2 ξ 1 , 2 q +3 × 2 ξ 0 , 3 l
ΔPOLY ξ ( q.l ;3) = 0
3
×
2 ξ 3 , 0 q +2 ξ 1 , 2 q +2 ξ 2 , 1 l +3
×
2 ξ 0 , 3 l =0
6 ξ 3 , 0 +2 ξ 1 , 2 =0
2 ξ 2 , 1 +6 ξ 0 , 3 =0
ξ 1 , 2 =
3 ξ 3 , 0
ξ 2 , 1 = 3 ξ 0 , 3
End of Example.
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