Geography Reference
In-Depth Information
+ 15
64 e 4 [ b 0 + 9
9
4 sin 4 b 0 + 7
12 sin 6 b 0 ]) + O( e 6 ) ,
4 sin 2 b 0
y 00 , e 2 e 2 =
3 a 1
32 ( b 0 +2sin2 b 0
5
4 sin 4 b 0 )+O( e 2 ) ,
=
y 01 ,e 2 =
3sin 2 b 0 + e 2 sin 2 b 0 )
2(1
a 1 (2
=
,
e 2 sin 2 b 0 ) 5 / 2
y 20 ,e 2 =
a 1 cos b 0 sin 3 b 0
4(1
=
e 2 sin 2 b 0 ) 3 / 2 ,
(21.76)
y 02 ,e 2 =
4 e 2 +3 e 2 sin 2 b 0
e 4 sin 2 b 0 )
= 3 a 1 cos b 0 sin b 0 (2
,
4(1 − e 2 sin 2 b 0 ) 7 / 2
y 21 ,e 2 =
= a 1 sin 2 b 0 (3 4sin 2 b 0 + e 2 sin 4 b 0 )
4(1
,
e 2 sin 2 b 0 ) 5 / 2
y 03 ,e 2 =
4 e 2
sin 2 b 0 (4
29 e 2 +27 e 4 )
2 e 2 sin 4 b 0 (11
18 e 2 +2 e 4 )
3 e sin 6 b 0 (3
e 2 )]
= a 1 [2
.
4(1 − e 2 sin 2 b 0 ) 9 / 2
Box 21.20 (Polynomial coecients of a conformal series of Box 21.11 of type Gauss-Krueger
or UTM after a curvilinear transformation, Easting X ( l
b 0 ,ρ,t x ,t y ,t z ,α,β,γ,s,δE 2 ),
l 0 ,b
second version).
U 00 = A 1
a 1 [( x 10 + x 10 ,e 2 δE 2 ) δL + x 11 δLδB ] ,
U 10 = A 1
a 1 ( x 10 + x 10 ,e 2 δE 2 + x 11 δB ) ,
U 01 = A 1
a 1 x 11 δL,
U 20 =3 A 1
a 1 x 30 δL,
 
Search WWH ::




Custom Search