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1
2 S E 2 A 1 ,A 2
1
4 A 1 (1
E 2 ) l E (sin B N
sin B S ) 1
=
×
(20.162)
1
+O 2 ( E 4 ) ,
3 E 2 sin 3 B N
sin 3 B S
2
×
sin B N
sin B S
l E
1
40
I AS =
E 2 ) 2 ×
(1
1
sin 3 B N
sin 3 B S
sin B N sin B S
sin 5 B N
sin 5 B S
sin B N sin B S
2
3
+ 1
5
×
×
(20.163)
1
+O 2 ( E 4 ) +
3 E 2 sin 3 B N sin 3 B S
2
×
sin B N
sin B S
+O S ( l E ) ,
I AS ( B N = −B S )= 1
40
l E
E 2 ) 2 ×
(1
1
3 sin 2 B N (1 + E 2 )+sin 4 B N 4
15 E 2 sin 6 B N +O 2 ( E 4 ) +
2
9 E 2 + 1
2
×
(20.164)
5
+O S ( l E ) .
End of Proof.
Proof (Riemann, l := L
L 0 ,b := B
B 0 ).
1 E 2 sin 2 B 0
1
Λ 1 =1+ cos 2 B 0
6
l 2 + 1
6
1 − E 2
E 2 sin 2 B 0 b 2 +O R ( l 3 ,b 3 ) , Λ 2 =1 ,
(20.165)
E 2
1
d S E 2 A 1 ,A 2 ( Λ 1 1) 2 = A 1 (1 E 2 )
+ l E
B N
1
2 S E 2 A 1 ,A 2
d B cos B ( Λ 1 1) 2
(1
I AR =
d l
E 2 sin 2 B ) 2 ,
(20.166)
2 S E 2 A 1 ,A 2
−l E
B S
1= cos 2 B 0
6
E 2 sin 2 B 0
1
E 2
1
l 2 + 1
6
1
1 − E 2 sin 2 B 0 b 2 +O R ( l 3 ,b 3 ) ,
Λ 1
(20.167)
E 2
1) 2 = cos 4 B 0
36
E 2 sin 2 B 0 ) 2
(1 − E 2 ) 2
E 2 ) 2
(1
l 4 + 1
36
(1
E 2 sin 2 B 0 ) 2 b 4
( Λ 1
(1
+ cos 2 B 0
18
l 2 b 2 +O R ( l 5 ,b 5 ) ,
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