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As a result, we compute
and obtain the series (the coecients [ μν ]are
collected in Box 20.5 and have to be computed at the point B 0 )
{
u =0 ,v = y
}
B 0 = [01] y + [02] y 2 + [03] y 3 + [04] y 4 +
B F
···
(a polynomial in y ) ,
(20.113)
L F
L 0 =0 , α F0
α 0F =0 ,
(20.114)
B F = B 0 +( B F
B 0 ) , L F = L 0 , α F0 = α 0F = π/ 2 .
Second step: determine L, B, γ, starting point
P F ,s = x = y c ,y = x c =0 FP = α F0 +3 π/ 2 = 0 given.
As a result, we compute
, which leads to the series (the coecients [ μν ]are
collected in Box 20.5 and have to be computed at the point B F )
{
u = x, v =0
}
B − B F = [20] x 2 + [40] x 4 + ···
(an even polynomial in x ) ,
L F = [10] x + [30] x 3 + [50] x 5 +
L
···
(an odd polynomial in x ) ,
(20.115)
α PF = γ = [10] α x + [30] α x 3 +
···±
π (an odd polynomial in x ) ,
B = B F +( B
B F ) ,
(20.116)
L = L F +( L
L F ) .
An alternative procedure is the following one-step method: set up a Taylor series for the
coecients [ μν ]in( 20.115 ), which have to be computed at the point B F , with B 0 as the
point of expansion, i.e.
0
∂B 2 0
2 [ μν ]
| 0 + [ μν ]
∂B
B 0 )+ 1
2!
B 0 ) 2 + hit([ μν ]) ,
[ μν ]
| F =[ μν ]
( B F
( B F
(20.117)
0 ( B F − B 0 )+ 1
0 ( B F − B 0 ) 2
[ μν ] α | F =[ μν ] α | 0 + [ μν ] α
2 [ μν ] α
∂B 2
∂B
2!
+hit([ μν ] α ) .
(20.118)
B 0 ) 2 etc. are computed from the first step, for instance,
The terms B F
B 0 , ( B F
0 y 2 + [03]
0 y 3 + [04]
0 y 4 +
B F
B 0 = [01]
|
0 y + [02]
|
|
|
···
,
(20.119)
B 0 ) 2 = ([01]
0 y 2 + [03]
0 y 3 + [04]
0 y 4 +
) 2 etc .,
( B F
|
0 y + [02]
|
|
|
···
leading to
 
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