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2+
η
0
(21
−
226
t
0
+ 105
t
0
)+
η
0
(19
−
34
t
0
+35
t
0
)]
,
1+2
t
0
+
η
0
2
N
0
,
[30]
α
=
t
0
(1 + 2
t
0
)
6
N
0
t
0
N
0
,
[11]
α
=
[10]
α
=
−
−
,
(20.96)
t
0
(5 + 6
t
0
)
6
N
0
,
[13]
α
=
1+20
t
0
+24
t
0
[12]
α
=
−
,
24
N
0
5+28
t
0
+24
t
0
24
N
0
[13]
α
=
−
.
Box 20.6 (Coecients of the solution of the boundary value problem with respect to the
Hamilton portrait
η
0
:=
E
2
/
(1
E
2
)cos
2
B
0
,
V
0
:= 1 +
η
0
,t
0
:= tan
B
0
).
−
1
V
0
N
0
,
(10) =
N
0
cos
B
0
,
(10) =
(20.97)
(20) =
3
η
0
t
0
2
V
0
N
0
,
(20) =
t
0
2
N
0
cos
2
B
0
,
(20.98)
t
0
V
0
N
0
cos
B
0
,
(11) =
−
(20.99)
2+2
η
0
+9
η
0
t
0
6
V
0
N
0
cos
B
0
,
(21) =
1
−
3
t
0
+
η
0
N
0
cos
2
B
0
,
(12) =
−
(20.100)
6
V
0
(30) =
η
0
(1
t
0
+
η
0
+4
η
0
t
0
)
2
V
0
t
0
−
6
N
0
cos
3
B
0
,
N
0
,
(30) =
−
(20.101)
η
0
t
0
(7
3
t
0
+7
η
0
+12
η
0
t
0
)
6
V
0
−
(13) =
−
N
0
cos
B
0
,
t
0
(1
−
t
0
+
η
0
)
6
V
0
N
0
cos
3
B
0
,
(31) =
−
(20.102)
t
0
+
η
0
)
24
(40) =
t
0
(1
−
N
0
cos
4
B
0
,
(20.103)
t
0
(4 + 3
η
0
+9
η
0
t
0
−
η
0
)
(22) =
−
N
0
cos
2
B
0
,
(20.104)
12
V
0
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