Geography Reference
In-Depth Information
Right metric tensor:
G r = r 2 0
= f 2 0
(18.10)
01
01
Left metric tensor:
G l = R 2 sin 2 Δ 0
R 2 , det[G l ]= R 4 sin 2 Δ.
(18.11)
0
Postulate of an equal area mapping:
det[C l ]=det[G l ] ⇒ ff g cos Δ =+ R 2 sin Δ
(only the + sign is here correct due to the orientation constance)
(18.12)
g =2 R 2 tan Δ
( f 2 )
= R 2 tan Δ
ff
.
(18.13)
General structure
(equal area mapping: pseudo-conic) :
α = α ( Λ, Δ )= g ( Δ ) Λ cos Δ =2 R 2 sin Δ
[ f 2 ( Δ )] Λ = R 2 sin Δ
ff Λ,
(18.14)
r = r ( Δ )= f ( Δ ) .
Proof.
( Λ S ) + =
tr[C l G l ]+ (tr[C l G l ]) 2
4det[C l G l ] ,
= 1
2
(18.15)
( Λ S ) =
tr [C l G l ]
4det[C l G l ] ,
(tr[C l G l ]) 2
= 1
2
det[C l ]=
 
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