Geography Reference
In-Depth Information
Right metric tensor:
G
r
=
r
2
0
=
f
2
0
(18.10)
01
01
Left metric tensor:
G
l
=
R
2
sin
2
Δ
0
R
2
,
det[G
l
]=
R
4
sin
2
Δ.
(18.11)
0
Postulate of an equal area mapping:
det[C
l
]=det[G
l
]
⇒ ff
g
cos
Δ
=+
R
2
sin
Δ
(only the + sign is here correct due to the orientation constance)
(18.12)
⇔
g
=2
R
2
tan
Δ
(
f
2
)
=
R
2
tan
Δ
ff
.
(18.13)
General structure
(equal area mapping: pseudo-conic) :
α
=
α
(
Λ, Δ
)=
g
(
Δ
)
Λ
cos
Δ
=2
R
2
sin
Δ
[
f
2
(
Δ
)]
Λ
=
R
2
sin
Δ
ff
Λ,
(18.14)
r
=
r
(
Δ
)=
f
(
Δ
)
.
Proof.
(
Λ
S
)
+
=
tr[C
l
G
−
l
]+
(tr[C
l
G
−
l
])
2
−
4det[C
l
G
−
l
]
,
=
1
2
(18.15)
(
Λ
S
)
−
=
tr [C
l
G
−
l
]
4det[C
l
G
−
l
]
,
(tr[C
l
G
−
l
])
2
=
1
2
−
−
det[C
l
]=
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